Write a script to test whether a year number is for a leap year or not.
eg. x = 1884
output = 1
eg. x = 3
output = 0
The test cases are too trivial. E.g. 2000 was a leap year, but 1900 or 1800 was not... (At least after the Gregorian calendar reform)
The test cases are to trivial. ;-)
more tests needed
Nice & simple - I like it!
Back to basics 4 - Search Path
Return the first and last character of a string
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