Write a script to test whether a year number is for a leap year or not.
eg. x = 1884 output = 1
eg. x = 3 output = 0
The test cases are too trivial. E.g. 2000 was a leap year, but 1900 or 1800 was not... (At least after the Gregorian calendar reform)
The test cases are to trivial. ;-)
more tests needed
Nice & simple - I like it!
Back to basics 3 - Temp Directory
273 Solvers
Remove the two elements next to NaN value
286 Solvers
235 Solvers
Finding perimeter of a rectangle
181 Solvers
116 Solvers