Cody

Problem 2510. Solving Quadratic Equations (Version 1)

Solution 3467668

Submitted on 29 Oct 2020 by Amaia Vicario Posadas
This solution is locked. To view this solution, you need to provide a solution of the same size or smaller.

Test Suite

Test Status Code Input and Output
1   Pass
qe_correct1_1 = -1; qe_correct1_2 = -2; [qe_result1_1, qe_result1_2] = SolveQuadraticEquation(1, 3, 2); assert( (abs(qe_result1_1 - qe_correct1_1) < 0.0001 && ... abs(qe_result1_2 - qe_correct1_2) < 0.0001) || ... (abs(qe_result1_1 - qe_correct1_2) < 0.0001 && ... abs(qe_result1_2 - qe_correct1_1) < 0.0001) );

x1 = -1 x2 = -2

2   Pass
qe_correct2_1 = 0.224745; qe_correct2_2 = -2.22474; [qe_result2_1, qe_result2_2] = SolveQuadraticEquation(2, 4, -1); assert( (abs(qe_result2_1 - qe_correct2_1) < 0.0001 && ... abs(qe_result2_2 - qe_correct2_2) < 0.0001) || ... (abs(qe_result2_1 - qe_correct2_2) < 0.0001 && ... abs(qe_result2_2 - qe_correct2_1) < 0.0001) );

x1 = 0.2247 x2 = -2.2247

3   Pass
qe_correct3_1 = -1; qe_correct3_2 = -1; [qe_result3_1, qe_result3_2] = SolveQuadraticEquation(2, 4, 2); assert( (abs(qe_result3_1 - qe_correct3_1) < 0.0001 && ... abs(qe_result3_2 - qe_correct3_2) < 0.0001) || ... (abs(qe_result3_1 - qe_correct3_2) < 0.0001 && ... abs(qe_result3_2 - qe_correct3_1) < 0.0001) );

x1 = -1 x2 = -1

Suggested Problems

More from this Author6

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!