Multiply matrix by each element of a vector without a for loop

If I have a matrix A and a vector v filled with scalars, how to I multiply A by each element of v, storing each result in an array as I go without using a for loop.
For example, if I have
A = [1,1;1,1]
v = [1,2,3]
I want to get an array M that is
M = {[A.*v(1)],[A.*v(2)],[A.*v(3)]} = {[1,1;1,1],[2,2;2,2],[3,3;3,3]}
Is there any way to do this without a for loop?

Antworten (3)

This may be considered ‘cheating’, however it does meet the requirements:
A = [1,1;1,1];
v = [1,2,3];
vr = repelem(v,2,2)
vr = 2×6
1 1 2 2 3 3 1 1 2 2 3 3
Ar = repmat(A,1,3)
Ar = 2×6
1 1 1 1 1 1 1 1 1 1 1 1
M = Ar.*vr
M = 2×6
1 1 2 2 3 3 1 1 2 2 3 3
Mc = mat2cell(M,2,ones(1,3)*2)
Mc = 1×3 cell array
{2×2 double} {2×2 double} {2×2 double}
Mc{1}
ans = 2×2
1 1 1 1
Mc{2}
ans = 2×2
2 2 2 2
Mc{3}
ans = 2×2
3 3 3 3
Generalising this to a different ‘A’:
A2 = [1 2; 3 4];
A2r = repmat(A2,1,3)
A2r = 2×6
1 2 1 2 1 2 3 4 3 4 3 4
M2 = A2r.*vr
M2 = 2×6
1 2 2 4 3 6 3 4 6 8 9 12
See the documentation for repmat, repelem, and mat2cell for details.
.
Stephen23
Stephen23 am 7 Jul. 2021
Bearbeitet: Stephen23 am 7 Jul. 2021
Let MATLAB do the heavy lifiting for you! Note that RESHAPE operations are computationally cheap as they do not change the array data themselves, just some of the mxArray meta-data.
A = [1,1;1,1];
v = [1,2,3];
C = num2cell(A.*reshape(v,1,1,[]),1:2);
C{:}
ans = 2×2
1 1 1 1
ans = 2×2
2 2 2 2
ans = 2×2
3 3 3 3
A = [1,1;1,1];
v = [1,2,3];
R = pagemtimes(A, reshape(v, 1, 1, []))
R =
R(:,:,1) = 1 1 1 1 R(:,:,2) = 2 2 2 2 R(:,:,3) = 3 3 3 3

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am 7 Jul. 2021

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am 7 Jul. 2021

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