index error is appearing for last line

1 Ansicht (letzte 30 Tage)
yogeshwari patel
yogeshwari patel am 1 Jun. 2021
U=zeros(1,2,'sym');
B=zeros(10,'sym');
U(1)=1;
U(2)=a;
for k=1:10
B(1)=0;
for i=1:k
B(1)=B(1)+U(i)*U(k-i+1)
end
end
It is displaying the error for B(1)=B(1)+U(i)*U(k-i+1)
  6 Kommentare
DGM
DGM am 2 Jun. 2021
Okay, that's one more bit of info, but that still doesn't clarify much. Why does B have 100 elements if you're only using one? Why does U only have 2 elements if you're trying to use 10 (actually you're now trying to use up to 11). I guess you could do like the answer below and just specify U to have 10 (or 11) elements instead of 2, but you're also assigning U(2) and then overwriting it.
I think what everyone is saying boils down to a common problem in communicating intent in code. The loop structure is incongruous when considering the array sizes. Since the intent and variable meaning are unknown at a conceptual level and the code as presented doesn't do what's desired, there's nothing left to tell us what it's supposed to do.
If offering a potential solution requires too many tenuous assumptions of intent, I don't think I'm alone in hesitating to add more confusion to the discussion by fishing with guesses.
yogeshwari patel
yogeshwari patel am 2 Jun. 2021
Thanks for your comment.

Melden Sie sich an, um zu kommentieren.

Akzeptierte Antwort

Girijashankar Sahoo
Girijashankar Sahoo am 1 Jun. 2021
B(1)=B(1)+U(i)*U(k-i+1)
% Here you defined length(U)=2 while U(i)*U(k-i+1) is over indexed value
% So my suggestion denfine U=zeros(1,10,'sym')

Weitere Antworten (0)

Kategorien

Mehr zu Matrix Indexing finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by