Info

This question is locked. Öffnen Sie sie erneut, um sie zu bearbeiten oder zu beantworten.

Tridiagonal Matrix with subdiagonal and main diagonal is also matrix

4 Ansichten (letzte 30 Tage)
Mücahit Özalp
Mücahit Özalp am 12 Mai 2021
Locked: Steven Lord am 13 Jul. 2024
I have two matrices A and B. I want A to be main diagonal and B to be my subdiagonals. How do I create such a matrix? By the way sizes of A and B changes but they are square matrices.
Specifically, a1=4,b1=-1
A =diag(a1*ones(1,N-1)) + diag(b1*ones(1,N-2),1) + diag(b1*ones(1,N-2),-1)
B=(-1)*eye(N-1)
These are my A and B matrices. I need to define a (N-1)*(N-1) times (N-1)*(N-1) matrix . For example for N=1000 or N=5000 I should be able to change the N value.
  14 Kommentare
Mücahit Özalp
Mücahit Özalp am 14 Mai 2021
Bearbeitet: Mücahit Özalp am 14 Mai 2021
@Matt JIt's me again now I can form the matrix for N=5000 but I need to evaluate its smallest 10 eigenvalues using E=eigs(D,10,'smallestabs'); I get out of memory error. Is there a way to solve that.
Matt J
Matt J am 14 Mai 2021
I don't think so, but if you post a new question on it (ideally with a demo), others on the forum may have some thoughts.

Akzeptierte Antwort

Matt J
Matt J am 12 Mai 2021
Bearbeitet: Matt J am 12 Mai 2021
So, you want a block Toeplitz matrix?
N = 5;
A =diag([7 4 4]);
B=[8 8 10; 2 5 2; 10 8 7];
C=zeros(3);
blocks={C,B,A};
result=cell2mat(blocks( toeplitz(1+[2,1,zeros(1,N-2)]) ))
result = 15×15
7 0 0 8 8 10 0 0 0 0 0 0 0 0 0 0 4 0 2 5 2 0 0 0 0 0 0 0 0 0 0 0 4 10 8 7 0 0 0 0 0 0 0 0 0 8 8 10 7 0 0 8 8 10 0 0 0 0 0 0 2 5 2 0 4 0 2 5 2 0 0 0 0 0 0 10 8 7 0 0 4 10 8 7 0 0 0 0 0 0 0 0 0 8 8 10 7 0 0 8 8 10 0 0 0 0 0 0 2 5 2 0 4 0 2 5 2 0 0 0 0 0 0 10 8 7 0 0 4 10 8 7 0 0 0 0 0 0 0 0 0 8 8 10 7 0 0 8 8 10
  8 Kommentare
Matt J
Matt J am 12 Mai 2021
N = 1000;
a1=4;b1=-1;
A =diag(a1*ones(1,N-1)) + diag(b1*ones(1,N-2),1) + diag(b1*ones(1,N-2),-1);
B=(-1)*speye(N-1) ;
C=sparse(N-1,N-1);
blocks={C,B,sparse(A)};
result=cell2mat(blocks( toeplitz(1+[2,1,zeros(1,N-3)]) ));
whos result
Name Size Bytes Class Attributes result 998001x998001 103680256 double sparse

Weitere Antworten (1)

Matt J
Matt J am 12 Mai 2021
Here's another way, probably much faster.
N=1000;
a1=4;b1=-1;
A =diag(a1*ones(1,N-1)) + diag(b1*ones(1,N-2),1) + diag(b1*ones(1,N-2),-1);
B=(-1)*eye(N-1);
E0=speye(N);
E1=E0(2:end,1:end-1);
E0=E0(1:end-1,1:end-1);
result=kron(E0,A) + kron(E1,B)+kron(E1.',B);
whos result
Name Size Bytes Class Attributes result 998001x998001 87760160 double sparse

This question is locked.

Kategorien

Mehr zu Operating on Diagonal Matrices finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by