Solving equation with tan

10 Ansichten (letzte 30 Tage)
Joel Schelander
Joel Schelander am 25 Mär. 2021
Beantwortet: Star Strider am 25 Mär. 2021
I have an equation that needs to be solved numerically.
-125=-arctan(0.25*x)-0.2*x*180/pi
I know that the answer can be approximatedto 6, according to the exams "corrected answer"
I cant solve it with pen and paper so I wonder if there is anyway to solve this in MATLAB?

Akzeptierte Antwort

Star Strider
Star Strider am 25 Mär. 2021
Here is how I would solve it:
fcn = @(x) 125-atand(0.25.*x)-0.2*x*180/pi;
est_x = fzero(fcn, 10)
producing:
est_x =
5.9959
See the documentation for fzero for details.

Weitere Antworten (0)

Kategorien

Mehr zu MATLAB finden Sie in Help Center und File Exchange

Tags

Produkte


Version

R2019a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by