How to return entire elements of a column of a matrix while that column includes maximum value of among all other elements of matrix

Hello,

Here it is my question:

I have follwoing 3*8 matrix:

A =
    0.0596    0.0714    0.8181    0.1499    0.9730    0.4538    0.0835    0.3909
    0.6820    0.5216    0.8175    0.6596    0.6490    0.4324    0.1332    0.8314
    0.0424    0.0967    0.7224    0.5186    0.8003    0.8253    0.1734    0.8034

What I want is finding the column which includs maximum value among all other elements of matrix and then returning all other elemnts of that column.

Considering my description ad question following matrix B (3*1) would be the answer which returns the all elemnts of fifth column which includs maximum value.

B =
     0.9730    
     0.6490    
     0.8003    

Can you please help me to write the script for that?

Thnaks in advance!

Milad

[dpb]

Milad -- it is EXTREMELY rude and non-productive to use poster IDs as tags.

Please DO NOT DO THIS GOING FORWARD!!

[Milad Naderloo]

Sorry! what is poster IS?

My apology if I used something wrong unintentionally!

[dpb]

IDS -- the user names of regulars here -- you used their names as Tags instead of something subject-related to your question, the whole point of there being tags.

Who provides a useful answer is immaterial and trying to attract somebody's attention to your specific Q? is not proper etiquette.

Answer 1

[dpb]

[~,ix]=max(max(A));    % return column of max of 2D array
B=A(:,ix);                    % the resulting column

Too bad there's no way to return the alternate return values as function result or could manage in one line/anonymous function. MATLAB syntax here requires the temporary variable.

NB: max(max()) uses default behavior of max (and most other MATLAB functions) to operate by column by default -- hence the inside max() returns a row vector of column max'es; the second then returns the location of the max in that vector--the desired column of the overall max in the array.

One could find the overall maximum location via

>> [~,i]=max(A,[],'all','linear')
i =
    13
>> [~,i]=max(A(:))
i =
    13
>> 

but one then would need to convert that linear location back to row, column by ind2sub

>> [r,c]=ind2sub(size(A),i)
r =
     1
c =
     5
>> 

requiring yet another temporary since the column is the second output form ind2sub

[Milad Naderloo]

Thank you so much! Now I corrected my script and it is working now!