Why the loop return only the last element ?
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I'm trying to change the size of subplots using a for loop.So what I really want to do is this:
clear
n=9;
pos=cell(1,n);
for i=1:n
a(i)=subplot(n,1,i);
pos{i}= get(a(i),'position');
if i<9
set(gca,'xtick',[])
end
pos{i}(1,4)=(pos{i}(1,4))/2;
set(a(i),'position',pos{i});
end
pos{8}(1,2)=(pos{8}(1,2)) - 0.045;
pos{7}(1,2)=(pos{7}(1,2)) - 0.09;
pos{6}(1,2)=(pos{6}(1,2)) - 0.1350;
pos{5}(1,2)=(pos{5}(1,2)) - 0.18;
pos{4}(1,2)=(pos{4}(1,2)) - 0.2250;
pos{3}(1,2)=(pos{3}(1,2)) - 0.2700;
pos{2}(1,2)=(pos{2}(1,2)) - 0.3150;
pos{1}(1,2)=(pos{1}(1,2)) - 0.3600;
set(a(8),'position',pos{8});
set(a(7),'position',pos{7});
set(a(6),'position',pos{6});
set(a(5),'position',pos{5});
set(a(4),'position',pos{4});
set(a(3),'position',pos{3});
set(a(2),'position',pos{2});
set(a(1),'position',pos{1});
But,I want to do this in a easier way .So I tried make all this using just a for loop :
clear
n=9;
pos=cell(1,n);
for i=1:n
a(i)=subplot(n,1,i);
pos{i}= get(a(i),'position');
if i<9
set(gca,'xtick',[])
end
pos{i}(1,4)=(pos{i}(1,4))/2;
for d=8:-1:0
y(d+1)=0.045*d;
t=fliplr(y);
end
pos{i}(1,2)=(pos{i}(1,2))-t(i);
set(a(i),'position',pos{i});
end
The point is that this code return only the last element.I mean,just the subplot(9,1,9).
How can I solve this ?
Thanks, Luiz
0 Kommentare
Akzeptierte Antwort
Ahmed A. Selman
am 10 Apr. 2013
It is a little tricky how loops are working in any program, aren't they? You used subplot and set and get within the same loop, this seems confusing matlab, and honestly I do not know exactly why. Also you calculated the values of (t) for 9 times.. which is needed only once.
So, try the code below, it may solve the problem:
clear
n=9;
pos=cell(1,n);
for d=8:-1:0
y(d+1)=0.045*d;
t=fliplr(y);
end
for i=1:n
a(i)=subplot(n,1,i);
pos{i}= get(a(i),'position');
end
for i=1:n
if i<9
set(gca,'xtick',[])
end
pos{i}(1,4)=(pos{i}(1,4))/2;
set(a(i),'position',pos{i});
pos{i}(1,2)=(pos{i}(1,2)) - t(i);
set(a(i),'position',pos{i});
end
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