How can I solve an equation with more than one variable?

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Aybike Elverdi
Aybike Elverdi am 1 Dez. 2020
Kommentiert: Aybike Elverdi am 1 Dez. 2020
Hi,
I have constants which are
G=44*10^3;
b=2.95e-10;
tao=0.02;
k=1.38e-23;
delta_fo=0.5;
epsilon_ref=10^6;
q=1.8;
p=0.3;
And also I have these variables
epsilon_p=[0.001,0.01,0.1,1,10]
T=[773,873,973,1073,1173]
My equation is
sigma_t=tao*G*(1-(((k*T)/(delta_fo*G*b^3*log(epsilon_ref/epsilon_p)))^(1/q))^(1/p))
I want to solve this equation for example epsilon_p=0.001 when T=773.
But can't do anything.Hope anyone can help me.

Akzeptierte Antwort

Stephan
Stephan am 1 Dez. 2020
Bearbeitet: Stephan am 1 Dez. 2020
You can solve for all cases in one calculation and save teh result as a matrix by using a function handle:
G=44*10^3;
b=2.95e-10;
tao=0.02;
k=1.38e-23;
delta_fo=0.5;
epsilon_ref=10^6;
q=1.8;
p=0.3;
epsilon_p=[0.001,0.01,0.1,1,10]
T=[773,873,973,1073,1173]
sigma_t= @(epsilon_p,T) tao*G*(1-(((k*T')./(delta_fo*G*b^3*log(epsilon_ref./epsilon_p))).^(1/q)).^(1/p))
sol = sigma_t(epsilon_p,T)
result:
sol =
1.0e+09 *
-0.2663 -0.3313 -0.4242 -0.5643 -0.7910
-0.3336 -0.4150 -0.5314 -0.7069 -0.9908
-0.4078 -0.5072 -0.6495 -0.8641 -1.2112
-0.4888 -0.6080 -0.7786 -1.0358 -1.4518
-0.5765 -0.7171 -0.9182 -1.2216 -1.7122
This works because of vectorization - on of the things that make Matlab great. Every row is one value of T and all the values of epsilon. Every column stands for changing T and the correspondig entry in epsilon:
>> Line3 = sigma_t(epsilon_p,T(3))
Line3 =
1.0e+09 *
-0.4078 -0.5072 -0.6495 -0.8641 -1.2112

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