How to fix it.

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Nisar Ahmed
Nisar Ahmed am 28 Okt. 2020
Kommentiert: Nisar Ahmed am 28 Okt. 2020
wav dimentions are
wav = 5001*1
and I want to change it as wav = 5001*5
How I can reshape it?

Akzeptierte Antwort

Steven Lord
Steven Lord am 28 Okt. 2020
So you want to take 5001 values and generate 25005 (5001 times 5) values using those values. How do you want to generate the additional 20004 values?
Make duplicate copies?
x = (1:6).'
y = repmat(x, 1, 5)
Offset the copies by a certain amount? This approach uses implicit expansion; if you're using an older release you could use bsxfun.
x = (1:6).'
y = x + (0:10:40)
Pad with 0 values or with random data?
x = (1:6).'
y = [x, zeros(size(x, 1), 5)]
z = [x, rand(size(x, 1), 5)]
w = [x, randi([7 11], size(x, 1), 5)]
Something else? If so, please explain in detail how you want to generate the additional values.
  3 Kommentare
Elijah McNeil
Elijah McNeil am 28 Okt. 2020
His code does that, Just write this.
x = (1:5000).';
wav = repmat(x, 1, 5).
Nisar Ahmed
Nisar Ahmed am 28 Okt. 2020
Elijah McNeil, thanks dear, Now it is working

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Weitere Antworten (1)

Elijah McNeil
Elijah McNeil am 28 Okt. 2020
Bearbeitet: Elijah McNeil am 28 Okt. 2020
This should work
wav = 5001*1
wav = wav*5
  5 Kommentare
Elijah McNeil
Elijah McNeil am 28 Okt. 2020
Wait 5000 rows and 1 column?
Nisar Ahmed
Nisar Ahmed am 28 Okt. 2020
5000 rows and 5 columns, each column is duplicate of other.

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