How t generate cone using scattered random point cloud?

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M.S. Khan
M.S. Khan am 20 Okt. 2020
Kommentiert: anuradha verma am 11 Nov. 2022
Using the below code, i have geneated sphere. could anyone please guide me how to geneate cone using random scattered point cloud.
I will be very thankful. Thanks in advance to all community members for their cooperation and guidance. Regards
r = randn (10000,3);
r = round(bsxfun(@rdivide,r,sqrt(sum(r.^2,2)))*130);
x = r(:,1);
y = r(:,2);
z = r(:,3);
scatter3(x,y,z)
  3 Kommentare
M.S. Khan
M.S. Khan am 20 Okt. 2020
Dear KSSV, thanks for your kind reply. This code provides cone also but not random scattered point cloud. Regards
M.S. Khan
M.S. Khan am 20 Okt. 2020
They are using grid that means its uniform spaced points? Could you guide me how to generate cone using scattered random point cloud.

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Bruno Luong
Bruno Luong am 20 Okt. 2020
Bearbeitet: Bruno Luong am 20 Okt. 2020
This code provides the uniform distribution on the surface of the cone
h = 3; % height
r = 1; % base radius
n = 1e4; % number of points
topcapflag = true; % include the top cap or not
rho = sqrt(rand(1,n));
z = h*rho;
if topcapflag
z(rand(1,n)<r/(h+r))=h;
end
theta = (2*pi)*rand(1,n);
rho = r*rho;
x = cos(theta).*rho;
y = sin(theta).*rho;
% graphic check
figure
plot3(x,y,z,'.')
axis equal

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Ameer Hamza
Ameer Hamza am 20 Okt. 2020
This is one way. The distribution is non-uniform
h = 2; % height of cone
r = 1; % maximum radius of cross section of the cone
n = 10000;
z = rand(1, n)*h;
t = rand(1, n)*2*pi;
r = interp1([0 h], [0 r], z);
[x, y] = pol2cart(t, r);
scatter3(x, y, z)
  23 Kommentare
Bruno Luong
Bruno Luong am 10 Nov. 2022
Bearbeitet: Bruno Luong am 10 Nov. 2022
@anuradha verma, it's not difficult, if you have new question, just click on Ask, or this link:https://mathworks.com/matlabcentral/answers/questions/new
then describe the problem accurately,.
This thread is opened by the author for his problem and it's has been answered.
You question merits a new thread

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