Calculate moving average manually

y[n] = 1/M Σx[n − k]

lower limit k= 0 upper limit M −1

Write a function that performs the moving average for any non-zero and positive order M. Make sure to add M-1 zeros at the beginning of the data so that your output data will be the same length as your input data.

I have this so far:

function [movaverage] = movaverage(M)
M=zeros(1,length(M));
for i=1:length(t)-M
    y1(i)=(1/M)*sum(i:i+M-1);
end
y=[zeros(1,M) y1];
figure
subplot(211)
plot(t,x,'b')
ylabel('Signal')
axis([0 3 0 30])
subplot(212)
plot(t,y,'r')
ylabel('Moving avg')
xlabel('Time (s)')
axis([0 3 0 inf])

[Ameer Hamza]

Since this is a homework question, show us what have you already tried? Read here: https://www.mathworks.com/matlabcentral/answers/6200-tutorial-how-to-ask-a-question-on-answers-and-get-a-fast-answer

[Image Analyst]

You need to give your function a name. You can't just have "function" on a line all by itself.

[Image Analyst]

OK, you fixed that. So now, what are M and t?

[Image Analyst]

No, that's worse. You pass in M but then you just go on to overwrite whatever was passed in with a different M. And you never said what M and t were like I directly asked.

[FS]

Thank you for your help. I understand how to calculate for a single value of M but I don't know how to convert this into a function that accepts any value of M.

[FS]

I managed to convert it to a function now, but I think I am missing something in the for loop.

M is the window size.

[Image Analyst]

You need an outer loop over n but not like you have. You need to use M, not k

for n=1:length(x)-(2*M+1) % M is the window width

Then the inner loop needs to be over k where k goes from 0 to M-1, just like your instructions said. Then you need to sum y and divide by M, again, like the instructions said, not like what you did which was to divide by (2*k+1). If you sum a sequence of M elements in y, then divide by M, you get the average value in that segment of y.

[FS]

Thank you!

[Rik]

If you want to avoid being caught cheating, you should not post your question to a website that is being cached by Google.

Moving average without using movmean() or conv()

Write a function that performs the moving average of any 1-dimensional input data for any non-zero and positive order M. Make sure to add M-1 zeros at the beginning of the data so that your output data will be the same length as your input data. You must not use built in functions like movmean() or conv().

y[n] = 1/M Σx[n − k]

lower limit k= 0 upper limit M −1

I have this so far:

function [movaverage] = movaverage(M)

M=zeros(1,length(M));

for i=1:length(t)-M
    y1(i)=(1/M)*sum(i:i+M-1);
end

y=[zeros(1,M) y1];

figure
subplot(211)
plot(t,x,'b')
ylabel('Signal')
axis([0 3 0 30])
subplot(212)
plot(t,y,'r')
ylabel('Moving avg')
xlabel('Time (s)')
axis([0 3 0 inf])

Answer 1

[Image Analyst]

I'm attaching a fully manual 2-D convolution. It should be easy for you to adapt it to 1-D

[Image Analyst]

I see you're editing the original question to follow my advice in my comment above:

"

You need an outer loop over n but not like you have. You need to use M, not k

for n=1:length(x)-(2*M+1) % M is the window width

Then the inner loop needs to be over k where k goes from 0 to M-1, just like your instructions said. Then you need to sum y and divide by M, again, like the instructions said, not like what you did which was to divide by (2*k+1). If you sum a sequence of M elements in y, then divide by M, you get the average value in that segment of y.

"

So, did that help you? Are we done yet and you can Accept this answer? Or do you still have questions?