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This question was flagged by Image Analyst

y[n] = 1/M Σx[n − k]

lower limit k= 0 upper limit M −1

Write a function that performs the moving average for any non-zero and positive order M. Make sure to add M-1 zeros at the beginning of the data so that your output data will be the same length as your input data.

I have this so far:

function [movaverage] = movaverage(M)

M=zeros(1,length(M));

for i=1:length(t)-M

y1(i)=(1/M)*sum(i:i+M-1);

end

y=[zeros(1,M) y1];

figure

subplot(211)

plot(t,x,'b')

ylabel('Signal')

axis([0 3 0 30])

subplot(212)

plot(t,y,'r')

ylabel('Moving avg')

xlabel('Time (s)')

axis([0 3 0 inf])

Image Analyst
on 10 Oct 2020

I'm attaching a fully manual 2-D convolution. It should be easy for you to adapt it to 1-D

Image Analyst
on 20 Oct 2020

I see you're editing the original question to follow my advice in my comment above:

"

You need an outer loop over n but not like you have. You need to use M, not k

for n=1:length(x)-(2*M+1) % M is the window width

Then the inner loop needs to be over k where k goes from 0 to M-1, just like your instructions said. Then you need to sum y and divide by M, again, like the instructions said, not like what you did which was to divide by (2*k+1). If you sum a sequence of M elements in y, then divide by M, you get the average value in that segment of y.

"

So, did that help you? Are we done yet and you can Accept this answer? Or do you still have questions?

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