Help me generating this series of number.

White flag.
I'm trying to make a series of number like below:
1
2
5
10
20
50
100
200
500
...
...
...
1000000000
2000000000
5000000000
but i need a for-end command first
for i=1:20
because i want to use that "20" in other procedure. And the generated numbers willl also be input in another procedure which requires them to be real positive integer.
could you help me?

 Akzeptierte Antwort

Andrei Bobrov
Andrei Bobrov am 17 Apr. 2011

0 Stimmen

without loop for
reshape(cumprod([1 2 5;10*ones(9,3)])',[],1);
with loop for
P = zeros(30,1);
for ii = 1:20
if rem(ii,2) == 0,
P(3*(ii/2)-2+(0:2)) = [1;2;5]*10^(ii/2-1);
end
end

3 Kommentare

Oleg Komarov
Oleg Komarov am 17 Apr. 2011
Slightly faster alternatives:
reshape(bsxfun(@times,[1; 2; 5], 10.^(0:9)),[],1);
reshape([1; 2; 5] * 10.^(0:9),[],1);
Albaihaqi Albaihaqi
Albaihaqi Albaihaqi am 18 Apr. 2011
May I ask?
why do you use
P(3*(ii/2)-2+(0:2))= ...
instead of
P(ii)= ...
?
Andrei Bobrov
Andrei Bobrov am 18 Apr. 2011
Because, it is necessary to fulfill your two conditions: length (P) = 30, i = 1:20

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Albaihaqi Albaihaqi
Albaihaqi Albaihaqi am 18 Apr. 2011

0 Stimmen

Thanks dude for a lot of help... I really need this...
Could I ask you for another problem I might have in the future? Thanks

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Hilfe-Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by