Plotting results in array of a while loop
6 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
Hicham Lhachimi
am 22 Jun. 2020
Kommentiert: Adam Danz
am 22 Jun. 2020
Hello,
I want to iteratively plot the results of my while loop, however, I end up with a blank graph or an error.
Here is the code:
Vlow=350;
fs=100000;
n=0.56;
Lk=41.98*0.000001;
P=10000;
Vhigh=900;
C=0;
i=0;
s=poly(0,"s");
while Vlow < 450
Polynome=((P*Lk*n*fs)/(Vhigh*Vlow))-s+s^2;
solution=roots(Polynome);
out = solution(solution<0.35 & solution>0.129);
I1=(1/(2*Lk*fs))*(2*(Vlow/n)*out+Vhigh-(Vlow/n));
I2=(1/(2*Lk*fs))*(2*Vhigh*out-Vhigh+(Vlow/n));
if I1 > I2 then
C= I1;
else
C=I2;
end
Y(i)=C;
X(i)=Vlow+20;
i=i+1;
end
plot(X,Y);
Any help would be greatly appreciated,
Thank you
8 Kommentare
Image Analyst
am 22 Jun. 2020
So s is this:
s =
1 -1 0.0746311111111111
which is a 1-by-3 vector, so it throws an error when you do this:
Polynome=((P*Lk*n*fs)/(Vhigh*Vlow))-s+s^2;
Were you expecting s to be a scalar instead of a 1-by-3 vector?
Akzeptierte Antwort
Adam Danz
am 22 Jun. 2020
Bearbeitet: Adam Danz
am 22 Jun. 2020
As the error message indicates, a subscript must be a real, positive integer or logical.
On the first iteration, i equals 0 which does not fulfill these requirements. 0 is not positive and it's not a logical value. So, when you index Y(i), or, Y(0), you get the error.
Instead of initializing i=0, set it to 1, i=1;
More importantly, the while-loop is defined by the value of Vlow but this value never changes within the while-loop so the while-loop will never end. Vlow will always be less than 450 because its original value is 350 which never changes within the loop.
Perhaps you meant to include something like this at the end of the while-loop.
Vlow = X(i);
If that's the case, then you could replace the while-loop with a for-loop since you know ahead of time the number of iterations. The number of iterations will be the number of values in
values = 350 : 20 : 450;
16 Kommentare
Adam Danz
am 22 Jun. 2020
Agreed. I almost always define loops as i = 1:n rather than i = some_vector.
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!