Values substitution of intervals.
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Michal Schreiner
am 3 Jun. 2020
Kommentiert: Michal Schreiner
am 3 Jun. 2020
Hello,
Its any easy way how to substitue interval in array with one value?
For example:
Values from 1400 to 1500 substitute with value 0.
Values from 1650 to 1750 substitute with 30.
Values from 1950 to 2000 substitue with 60.
I know about x(x<trehshold)=0 , but i need to use interval.
Thanks for reply!
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madhan ravi
am 3 Jun. 2020
Bearbeitet: madhan ravi
am 3 Jun. 2020
interval1 = (x >= 1400) & (x <= 1500);
interval2 = (x >= 1650) & (x <= 1750);
interval3 = (x >= 1950) & (x <= 2000);
x(interval1) = 0;
x(interval2) = 30;
x(interval3) = 60
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