Getting a constant instead of (2*exp(-3/2))/3 + 1/3 solving a differential equation

I want to get a constant number instead of (2*exp(-3/2))/3 + 1/3 solving a differential equation.

I have used dsolve() to find the solution;

Then,I have used sub() to substitute the parameter with a constant to get a number.

But I dont get any number.

Can anyone help with this?

[John D'Errico]

That is a constant number. Just not in floating point form. If that is what you want, then use Star's suggestion. Either double or vpa will do it.

Answer 1

[Star Strider]

Use the vpa or double function, depending on the result you want.

Answer 2

[Sohan Mahmud]

Use sym2poly() after using subs().