Why doesn't .3 - .2 - .1 = 0

2 Ansichten (letzte 30 Tage)
Lucas
Lucas am 9 Nov. 2012
I was bored yesterday at work and I was playing around with some decimal numbers when I stumbled across something I thought was pretty interesting.
.3 - .2 - .1 != 0
but
.2 - .1 - .1 = 0
then I began to run some other tests and I found out that only .3 and .8 are the only numbers that you use that'll not get you a 0 answer. If you take:
.4 - .2 - .1 - .1 = 0
and
.9 -.2 -.1 -.1 -.1 -.2 -.1 -.1 = 0
If you change any of the .2's to two - .1's you don't get 0. So what’s so special about those 2 decimals that make them the only ones that don't work with basic subtraction?

Akzeptierte Antwort

Matt J
Matt J am 9 Nov. 2012
Bearbeitet: Matt J am 9 Nov. 2012
What makes them special? Nothing. There are lots more numbers like that
>> isequal(0, .7 - .5 - .2)
ans =
0
It also depends on the operation you do. Sometimes 0.3 will work fine, e.g.,
>> isequal(0, .6 - .3 -.3)
ans =
1
  2 Kommentare
Matt Fig
Matt Fig am 9 Nov. 2012
It is not just in MATLAB. ALL numerical systems that follow IEEE 754 will behave this way. That is the standard.
José-Luis
José-Luis am 9 Nov. 2012
Bearbeitet: José-Luis am 9 Nov. 2012
This is not Matlab specific. It has to do with the fact that computers use binary numbers and humans tend to feel more comfortable with decimals. Things gets lost in translation and these are the side effects.

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Weitere Antworten (1)

Thomas
Thomas am 9 Nov. 2012
Bearbeitet: Thomas am 9 Nov. 2012
This should answer your question. Look at the wiki under the section Why_is_0.3_-_0.2_-_0.1_.28or_similar.29_not_equal_to_zero? (might have to scroll on the page to locate...)
  2 Kommentare
Dr. Seis
Dr. Seis am 9 Nov. 2012
Bearbeitet: Dr. Seis am 9 Nov. 2012
I had similar issues when doing mod(0.4,0.4) and mod(0.8,0.4) returning a number slightly smaller than 0.4 instead of 0. Whenever I do these types of comparisons in the future I will need to overload the builtin functions.
Oleg Komarov
Oleg Komarov am 9 Nov. 2012
@Lucas, if you already know that you wouldn't be asking the question in the first place. I recommend to read the FAQ more carefully.

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