indexing of an array of index

Hi!

    % for l=1:length(date_l)    
[~, ind(l)] = min(abs(numdates-(date_l(l))));
end

i get the array ind

How could i get the ind of the minimum and the two index before and the two after ?

what should i change here [~,ind(l)] to get the result?

Thank you

Answer 1

[Andrei Bobrov]

index = bsxfun(@plus,ind(:),-2:2);

OR full solution

index = bsxfun(@plus,min(abx(bsxfun(@minus,numdates(:),date_l(:).'))),(-2:2).');

Answer 2

[Rica]

that is really great. how do find in google something like this? i try it to find it myself before i asked the question...

thanks again