How to get the coordinates of each room in a floor plan image through object identification method?
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I have a floor plan image which contains objects and walls. I removed all the objects in it so it now contains only walls. Now I want to get the coordinates of each room.
I am new to this platform. Can somebody please help me how to get the coordinates of each room? Or Can I get the end points of each line segment?
This is the code.
function [bbox_loc,sign_objects,index1,st,furniture]=classify_objects_test1(I1)
% clear all;
% clc;
% close all;
I_initial=imread("C:\\Users\\User\\Desktop\\tkinter_codes\\floorplans\\ROBIN\\Dataset_3roomsmall\\Cat1_1.jpg");
%I_initial = imread('room_4.png');
I=I_initial;
imshow(I);
SE = strel('square',10);
I = imdilate(I,SE);
SE = strel('square',10);
I = imerode(I,SE);
wall_image=I;
wall = I;
I=I_initial;
wall=im2bw(wall);
imshow(wall);
I=im2bw(I);
I=imcomplement(I);
wall = imcomplement(wall);
I=I-wall;
% imshow(I);
I=imcomplement(I);
SE = strel('square',1);
IM2 = imdilate(I,SE);
IM2 = I;
IM2 = imerode(IM2,SE);
imwrite(IM2,'fl_0sym.tif');
se1=strel('square',8);
intm1=imerode(IM2,se1);
se2=strel('square',4);
intm2=imdilate(intm1,se2);
intm3=imdilate(intm2,se2);
imwrite(intm3,'fl_0sym1.tif');
I = imread('fl_0sym1.tif');
I = imcomplement(I);
J = imfill(I);
J = ~J;
imwrite(J,'blb_0_1.jpg');
figure=I_initial;
[m,n] = size(figure);
figure1 = figure(:,:,[1 1 1]);
figure = im2bw(figure);
[m,n] = size(figure);
image = imread('blb_0_1.jpg');
BW = im2bw(image);
BW = imresize(BW,[m,n]);
BW = ~BW;
%for 4,1,9,8
SE = strel('square',10);
BW = imdilate(BW,SE);
%% figure;imshow(BW);
st = regionprops(BW,'BoundingBox');
shape.Inserter = vision.ShapeInserter('LineWidth',4,'BorderColor','Custom','CustomBorderColor',uint8([255 0 0]));
str_ele=strel('disk',1,0);
for k = 1:length(st)
% k=1;
% for k = 1:1
thisBB = st(k).BoundingBox;
%figure1 = step(shape.Inserter,figure1,bbox_loc{k});
thisBBarea=thisBB(3)*thisBB(4);
if thisBB(3)>20 && thisBB(4)>20
rectangle = int32([thisBB(1),thisBB(2),thisBB(3),thisBB(4)]);
end
if(thisBBarea >870)
bbox_loc{k}=rectangle;
crop_I_new=imcrop(figure1,rectangle);
crop_I_new_gray=rgb2gray(crop_I_new);
crop_I=im2bw(crop_I_new_gray,0.7);
% figure;imshow(crop_I);
signature{k}=signature_find(crop_I);
if isempty(signature{k})
signature{k}=[99999,99999,99999];
end
figure1 = step(shape.Inserter,figure1,bbox_loc{k});
end
end
signature=signature(~cellfun('isempty',signature));
save('signature.mat','signature');
signature=load('signature.mat');
sign_objects=load('sign_object2');
for i=1:length(signature.signature)
for j=1:length(sign_objects.sign_object2)
diff{i,j}=abs(signature.signature{1,i}-sign_objects.sign_object2{j,1}.count);
end
end
for(i=1:size(diff,1))
for(j=1:size(diff,2))
if(sign_objects.sign_object2{j,1}.count(3)>1000)
temp1(i,j)=diff{i,j}(1)+diff{i,j}(2);
else
temp1(i,j)=diff{i,j}(1)+diff{i,j}(2)+diff{i,j}(3);
end
end
end
for(i=1:size(temp1,1))
[temp1_min(i),index1(i)]=min(temp1(i,:));
disp(sign_objects.sign_object2{index1(i),2});
furniture{i,1}=sign_objects.sign_object2{index1(i),2}
figure;imshow(figure1);
bbox_loc=bbox_loc(~cellfun('isempty',bbox_loc));
end
for k = 1:length(bbox_loc)
H= text( double(bbox_loc{k}(1)),double(bbox_loc{k}(2)),sign_objects.sign_object2{index1(k),2});
set(gcf,'DefaultTextColor','blue')
end
% for i=1:size(diff,1)
% for j=1:size(diff,2)
%
% temp1(i,j)=(diff{i,j}(1));
% temp2(i,j)=(diff{i,j}(2));
% temp3(i,j)=(diff{i,j}(3));
%
%
% end
% [temp1_min(i),index1(i)]=min(temp1(i,:));
% disp(sign_objects.sign_object1{index1(i),2});
% furniture{i,1}=sign_objects.sign_object1{index1(i),2}
% end
I am attaching a zip file which contains files which will be used by this code while running.
This is the floorplan image with objects.

This is the image with only walls.

Akzeptierte Antwort
Weitere Antworten (1)
Matt J
am 9 Mai 2020
0 Stimmen
The Computer Vision Toolbox has a few corner detection routines,
7 Kommentare
CHINTALA NIRMAL SRINIVAS
am 9 Mai 2020
Image Analyst
am 9 Mai 2020
But, just scanning your code, it looks like you get the bounding boxes, so that gives you the coordinates of each room, right?
CHINTALA NIRMAL SRINIVAS
am 9 Mai 2020
CHINTALA NIRMAL SRINIVAS
am 9 Mai 2020
Image Analyst
am 9 Mai 2020
Call bwskel() to get the skeleton of the walls
skelImage = bwskel(~mask);
Then get the endpoints of that image with bwmorph. Call pdist2() to get all the distances between endpoints. If the endpoints are within a certain distance (whatever a door width is), AND either the rows are the same or the columns are the same (so we're only getting vertical or horizontal gaps), then draw a line connecting the room going across the doorway.
There are hundreds of algorithms for getting floor plans that have been published here:
Look them over and code up the most promising one.
CHINTALA NIRMAL SRINIVAS
am 9 Mai 2020
CHINTALA NIRMAL SRINIVAS
am 9 Mai 2020
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