How to build on an existing struct 4x4xn matrix?
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Happy PhD
am 28 Apr. 2020
Kommentiert: Rik
am 28 Apr. 2020
I have an struct, for example...
A = struct();
where we have a 4x4 matrix
A.G = rand(4,4);
I want to build on values within the (4x4) matrix but stack new values in a n'th dimension.
How do I build on the maxtrix in the n'th dimesnion if I don't know how many non-zero values exist in respective field A.G(1,1,n), A.G(1,2,n), A.G(2,2.n) and A.G(4,4,n). the n't value can stack randomly. I wan't to know how many non-zero values lies behind for example A.G.(1,2,n) where n is a unkown value depending how many values i already put into A.G(1,2,n), which i don't keep track on.
4 Kommentare
Mrutyunjaya Hiremath
am 28 Apr. 2020
Hello Happy PhD,
do you want to add next value where there are 0's are there?
Akzeptierte Antwort
Mrutyunjaya Hiremath
am 28 Apr. 2020
Hello Happy PhD,
Try this one...
clc;
clear all;
A.G(:,:,1) = [1 2 1 1 ; 4 9 5 6 ];
A.G(:,:,2) = [0 1 0 0; 0 6 0 0];
A.G(:,:,3) = [0 5 0 0; 0 0 0 0];
N = 10; % random number
idx = find(A.G == 0);
if ~isempty(idx)
A.G(idx(1)) = N;
else
n = size(A.G,3);
A.G(1,1,n+1) = N;
end
disp(A.G);
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Rik
am 28 Apr. 2020
It sounds like you can just assign that value. Matlab will expand the array and fill empty positions with 0.
A.G=cat(3,[ 1 2 0 1 ; 4 9 5 6 ], [ 0 1 0 0; 0 6 0 0],[0 5 0 0; 0 0 0 0 ]);
A.G(1,2,4)=8;%Matlab fills the 4th page with zeros
disp(A.G)
2 Kommentare
Rik
am 28 Apr. 2020
You can find the first empty page like this:
[r,c,val]=deal(1,2,8);
A.G=cat(3,[ 1 2 0 1 ; 4 9 5 6 ], [ 0 1 0 0; 0 6 0 0],[0 5 0 0; 0 0 0 0 ]);
N_by_rc=sum(logical(A.G),3)+1;
n=N_by_rc(r,c);
A.G(r,c,n)=val;
clc,disp(A.G)
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