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Repeating a day of the year sequence from a specified date input

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Bailey Adams
Bailey Adams on 26 Apr 2020
Commented: Bailey Adams on 27 Apr 2020
I'm trying to repeat a day of the year sequence in a for loop after the "day_num_index" reaches day 365. I want it to repeat the sequence (day 1 - day 365) and start over at day 1 after day 365 is reached. I need it to loop through for a specified number of iterations until the final index of the loop is reached. Additionally, the code should be compatible with any initial specified date (i.e. 1-Oct-2020 in the example provided below) throughout the year.
Anyone have some suggestions?

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Answers (1)

Peter Perkins
Peter Perkins on 27 Apr 2020
Right off the bat, 365 is a bug. I can't tell if you want to start at, say, 1-Oct-2020, and increment the day until you get to 31-Dec-2020 and wrap around to 1-Jan-2020 and keep going like that until you've had 1000 iterations, or if you want to increment the day until you get to 30-Sep-2021 and wrap around to 1-Oct-2020 and keep going like that until you've had 1000 iterations.
In either case, just let datetime do the incrementing and you do the modulo. Something like
startDate = datetime(2020,10,1);
wrapDate = dateshift(startDate,'start','year','next') - caldays(1);
% or wrapDate = startDate + calyears(1) - caldays(1);
d = startDate - caldays(1);
for i = 1:1000
if d == wrapDate
d = d - calyears(1);
end
d = d + caldays(1);
disp(d)
end

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Bailey Adams
Bailey Adams on 27 Apr 2020
I'd like to start at any input date, increment that day until 31-Dec, and then wrap around to 1-Jan and continue for a specified number of iterations in the loop (like the first part of your statement)!

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