I want to count the number of times each event (a, b, c... up until j) occurs, a(t<1 hour) b(1 hour<t<2 hours) c(2 hours<t<3 hours)... up to j( t>9 hours) based on the following sample in order to find the probability of any individual event occuring

'02:47:09'

'03:28:26'

'13:57:18'

'08:58:46'

'10:31:50'

'11:03:35'

'09:11:01'

'01:37:30'

'04:38:33'

'03:02:50'

'05:41:13'

'01:21:29'

'04:44:26'

'01:06:18'

'03:47:08'

'03:33:12'

'05:30:32'

'08:48:40'

'00:00:02'

'08:52:09'

'04:57:18'

'03:47:12'

'03:39:37'

'03:28:25'

'00:43:12'

'03:41:52'

'03:47:26'

'08:00:04'

'01:16:49'

'01:00:12'

'00:01:34'

'04:28:35'

'14:28:52'

'05:46:56'

'02:38:23'

'00:01:19'

'06:21:24'

'05:38:55'

'01:05:57'

'13:36:44'

Answer 1

[David Hill]

If your data is not in a cell array, convert to a cell array. For example:

A={'02:47:09';'03:28:26';'13:57:18';'08:58:46';'10:31:50'};
A=hours(duration(A));
a=nnz(A<1);
b=nnz(A>=1&A<2);
c=nnz(A>=2&A<3);
d=nnz(A>=3&A<4);
e=nnz(A>=4&A<5);
f=nnz(A>=5&A<6);
g=nnz(A>=6&A<7);
h=nnz(A>=7&A<8);
i=nnz(A>=8&A<9);
j=nnz(A>=9);

[Stephen23]

Repeated code is not very generalized, but could easily be replaced by a histogram function.

[GS25]

Thank you guys!