How to solve for 4 variables from 5 equations that I have derived.

Hi, I have a problem in MATLAB. I am doing research in Optics ... I have to find 4 values from 5 equations and having some trouble. Kindly help.
I have tried reg this as below: I would be grateful to have any suggestions. Thanks in advance
clear
T = 0.89; R = 0.11; lamda = 0.98; d = 1.65; pi = 3.14; phit = 0.6; phir = 0.31; %((-(a))*d) == (23.03)*k;
% sym a b n k; % a and b are "alpha" and "beta"
a = sym('a'); b = sym('b'); n = sym('n'); k = sym('k');
eq1 = T == '({(1-R)^2+4*R*(sin(phir))^2}*exp((-a)*d))/((1-R*exp((-a)*d))^2+4*R*exp((-a)*d)*(sin(b+phir))^2)';
eq2 = (phit) == '((2*(pi)*n*d)/lamda)-(atan((k(n^2+k^2-1))/((k^2+n^2)*(2+n)*n)))+(atan((R*exp((-a)*d))*(sin2(b+phir))/(1-R*exp((-a)*d)*cos2(b+phir))))';
eq3 = (phir) == 'atan(((-2)*k)/(1-((n)^2)-((k)^2)))';
eq4 = (b) == '((2*(pi)*n*d)/lamda)';
eq5 = (a) == '((4*(pi)*k)/lamda)';
%eq6 = (e) == '((-(a))*d) == (23.03)*k';
[a b n k] = solve(eq1,eq2,eq3,eq4,eq5,a,b,n,k);

Antworten (4)

Azzi Abdelmalek
Azzi Abdelmalek am 2 Okt. 2012
Bearbeitet: Azzi Abdelmalek am 2 Okt. 2012
Corrected code
syms a b n k;
eq1 ='T==(((1-R)^2+4*R*(sin(phir))^2)*exp((-a)*d))/((1-R*exp((-a)*d))^2+4*R*exp((-a)*d)*(sin(b+phir))^2)';
eq2 = 'phit==((2*(pi)*n*d)/lamda)-(atan((k(n^2+k^2-1))/((k^2+n^2)*(2+n)*n)))+(atan((R*exp((-a)*d))*(sin2(b+phir))/(1-R*exp((-a)*d)*cos2(b+phir))))';
eq3 = 'phir==atan(((-2)*k)/(1-((n)^2)-((k)^2)))';
eq4 = 'b==((2*(pi)*n*d)/lamda)';
eq5 = 'a==((4*(pi)*k)/lamda)';
sol= solve(eq1,eq2,eq3,eq4,eq5,a,b,n,k)
but it seems that you system does'nt have solutions. Notice that you have more equations then unknown variables
Shaumik
Shaumik am 2 Okt. 2012

0 Stimmen

Thanks a lot for your help Azzi.. I will work on this and get back.
Shaumik
Shaumik am 4 Okt. 2012

0 Stimmen

hello
I just put in the value of 'a' in the equations (program given below the error message), but getting this error. Any suggestions would be very helpful. Thanks
________________________________________
??? Error using ==> solve>getEqns at 182 ' T==((1-R)^2)+((4)*(R)*(sin(phir)^2))*(exp((-((4*(pi)*k)/(lamda)))*(d)))/((1)-(R)*(exp(((4*(pi)*k)/(lamda))*(d)))^2)+((4)*(R)*(exp(((4*(pi)*k)/(lamda))*(d)))*(sin(b+phir)^2)) ' is not a valid expression or equation.
Error in ==> solve at 67 [eqns,vars] = getEqns(varargin{:});
Error in ==> RI at 19 sol = solve(eq1,eq2,eq3,eq4,b,n,k);
________________________________________________________
T = 0.89; R = 0.11; lamda = 0.98; d = 1.65; pi = 3.14; phit = 0.60; phir = 0.31;
syms b n k;
eq1 = 'phir==atan(((-2)*k)/(1-((n)^2)-((k)^2)))';
eq2 = 'T==((1-R)^2)+((4)*(R)*(sin(phir)^2))*(exp((-((4*(pi)*k)/(lamda)))*(d)))/((1)-(R)*(exp(((4*(pi)*k)/(lamda))*(d)))^2)+((4)*(R)*(exp(((4*(pi)*k)/(lamda))*(d)))*(sin(b+phir)^2))';
eq3 = 'phit==((2*(pi)*n*d)/(lamda))-(atan((k(n^2+k^2-1))/((k^2+n^2)*(2+n)*n)))+(atan((R*exp(((4*(pi)*k)/(lamda))*d))*(sin2(b+phir))/(1-R*exp(((4*(pi)*k)/(lamda))*d)*cos2(b+phir))))';
eq4 = 'b==(((2)*(pi)*(n)*(d))/(lamda))';
%eq5 = 'a==((4*(pi)*k)/(lamda))';
sol = solve(eq1,eq2,eq3,eq4,b,n,k);

4 Kommentare

Change the == to =
Thanks Walter.
I changed the equal sign and it gave the following error:
Warning: Explicit solution could not be found.
So, do I have to try with fsolve or are there any other means to solve these equations.
Thanks for the help
Walter Roberson
Walter Roberson am 4 Okt. 2012
Bearbeitet: Walter Roberson am 4 Okt. 2012
What are sin2() and cos2() ? If you want sin-squared you need sin(x)^2
yes, you are right. i may have made a mistake there.
I am correcting that and trying again.
thanks for the help.

Melden Sie sich an, um zu kommentieren.

Shaumik
Shaumik am 4 Okt. 2012

0 Stimmen

sorry to bother again.. I changed the sin-square and cos-square, but still the same error is coming. Dont know where I am going wrong.
Anyway.. I am keeping on trying.. meanwhile if you think of anything else that might help, please let me know. Would really appreciate it.
Thanks Walter for all the help.

Kategorien

Mehr zu Programming finden Sie in Hilfe-Center und File Exchange

Tags

Gefragt:

am 2 Okt. 2012

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by