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Why it plots more than just one point and how do I get rid of them

1 Ansicht (letzte 30 Tage)
Stefania Maria
Stefania Maria am 10 Dez. 2019
Geschlossen: MATLAB Answer Bot am 20 Aug. 2021
function xp=h2(t,x)
xp=x;
xp(1)=(x(2)) .^2 - 70.*x(2);
xp(2)=(x(1)) .^2 +134.*x(1) - 64 .*x(2);
hold on
[t,x]=ode23('h2', [0,100], [0,0]);
plot(x(:,1), x(:,2), 'kx')
[t,x]=ode23('h2', [0,100], [-64,70]);
plot(x(:,1),x(:,2), 'bx')
[t,x]=ode23('h2', [0,100], [-134,0]);
plot(x(:,1), x(:,2), 'kx')
[t,x]=ode23('h2', [0,100], [55.4/2,70]);
plot(x(:,1), x(:,2), 'kx')
[t,x]=ode23('h2', [0,100], [-323.4/2,70]);
plot(x(:,1), x(:,2), 'kx')
When I plot [-64,70] (stable node) and [55.4/2,70] (saddle), it doesn't appear just one 'x' on the given coord. but it plots a spiral of 'x's starting from those points to [0,0] (focus) point. How do I make the spiral disappear, and have only one 'x' point for each coord?

Antworten (1)

Star Strider
Star Strider am 10 Dez. 2019
The code plots more than one point because you told it to.
Revised code:
function xp=h2(t,x)
xp=zeros(2,1);
xp(1)=(x(2)) .^2 - 70.*x(2);
xp(2)=(x(1)) .^2 +134.*x(1) - 64 .*x(2);
end
hold on
[t,x]=ode23(@h2, [0,100], [0,0]);
plot(x(:,1), x(:,2), 'kx')
[t,x]=ode23(@h2, [0,100], [-64,70]);
plot(x(:,1),x(:,2), 'bx')
[t,x]=ode23(@h2, [0,100], [-134,0]);
plot(x(:,1), x(:,2), 'kx')
[t,x]=ode23(@h2, [0,100], [55.4/2,70]);
plot(x(:,1), x(:,2), 'kx')
[t,x]=ode23(@h2, [0,100], [-323.4/2,70]);
plot(x(:,1), x(:,2), 'kx')
hold off
What result do you want?
  2 Kommentare
Stefania Maria
Stefania Maria am 10 Dez. 2019
It still doesn't work.
I only need five points on the graphScreenshot (17).png
Star Strider
Star Strider am 10 Dez. 2019
Bearbeitet: Star Strider am 10 Dez. 2019
Replace ‘[0,100]’ for the ‘tspan’ argument with:
tv = linspace(0, 100, 5);
Then use that in every ode45 call:
hold on
[t,x]=ode23(@h2, tv, [0,0]);
plot(x(:,1), x(:,2), 'kx')
[t,x]=ode23(@h2, tv, [-64,70]);
plot(x(:,1),x(:,2), 'bx')
[t,x]=ode23(@h2, tv, [-134,0]);
plot(x(:,1), x(:,2), 'kx')
[t,x]=ode23(@h2, tv, [55.4/2,70]);
plot(x(:,1), x(:,2), 'kx')
[t,x]=ode23(@h2, tv, [-323.4/2,70]);
plot(x(:,1), x(:,2), 'kx')
hold off
That will produce five points for every ode45 call.
If you only want five points total, you need to choose which points you want to plot.
That might require:
hold on
[t,x1]=ode23(@h2, tv, [0,0]);
plot(x1(end,1), x1(end,2), 'kx')
[t,x2]=ode23(@h2, tv, [-64,70]);
plot(x2(end,1),x2(end,2), 'bx')
[t,x3]=ode23(@h2, tv, [-134,0]);
plot(x3(end,1), x3(end,2), 'kx')
[t,x4]=ode23(@h2, tv, [55.4/2,70]);
plot(x4(end,1), x4(end,2), 'kx')
[t,x5]=ode23(@h2, tv, [-323.4/2,70]);
plot(x5(end,1), x5(end,2), 'kx')
hold off
Or something similar.
Experiment to get the result you want.

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