3D Point Cloud - Gaussian Curvature

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RiHo
RiHo am 25 Nov. 2019
Kommentiert: darova am 4 Dez. 2019
Hello All.
I have a 3D point cloud data (X [m]; Y[m]; Z[m]). And I want to calculate the value of some curvature (e.g. gaussian) in every point of the point cloud. Based on these curvature information I would select the points, that may belong to some geometric shape in the point cloud (e. g. to some planes, spheres etc.).
Is there a built in function for it in Matlab, like normals() for normal vector estimation? Or does anyone know a way how to do this? It should be fast and dont need to be really precise, because it is only a pre-processing step.
Thanks in Advance,
Richard

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darova
darova am 26 Nov. 2019
one way
clc,clear
% generate some data
r = 3;
t = linspace(0,10)';
x = r*cos(t);
y = r*sin(t);
z = sin(1*t);
t1 = t(2:end) - diff(t)/2;
dv = diff([x y z])./diff([t t t]); % first derivative at midpoints
d2v= diff(dv)./diff([t1 t1 t1]); % second derivative at points [2:end-1]
dv = 1/2*( dv(1:end-1,:) + dv(2:end,:) );% first derivative at points [2:end-1]
[dx,dy,dz] = deal( dv(:,1),dv(:,2),dv(:,3) );
[d2x,d2y,d2z] = deal( d2v(:,1),d2v(:,2),d2v(:,3) );
% curvature
kk = (d2z.*dy - d2y.*dz).^2 + (d2x.*dz - d2z.*dx).^2 + (d2y.*dx - d2x.*dy).^2;
kk = sqrt(kk) ./ (dx.^2+dy.^2+dz.^2).^(3/2);
% radius
RR1 = 1./kk;
plot(t(2:end-1),RR1)
03b2b952dac167188878f3898be17b9861c3c86a
  10 Kommentare
RiHo
RiHo am 4 Dez. 2019
I dont think so, because scanned point clouds have really rugged surface, like when you imagine point cloud of complex objects like buildings and so on. There are lot of complicated surfaces.
That's why I'm fitting a local small plane in every point for point normal vector computation, like in pcnormals.
darova
darova am 4 Dez. 2019
If you can get normals for neighbouring points:
alpha = acos(dot(n1,n2));
123.png

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