Functions Matlab, how to modify?

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Jenny Andersen
Jenny Andersen am 24 Nov. 2019
Kommentiert: Jenny Andersen am 25 Nov. 2019
Hi,
so I have two vectors, Q = (a,l,m) and Z = (d,b,c). I have created a function to calculate Z, but the problem is that I don't want the answear to be d= something1, b=something2 and c= something3. I want it to be Z = =[something1, something2, something3] when I call the function.
function [a,l,m]=test1(d,b,c)
a=0;
l=b/sqrt(b^2 + c^2);
m=c/sqrt(d^2 + c^2);
a=a*1;
a=a*-1;
l=l*1;
l=l*-1;
m=m*1;
m=m*-1;
Is it possbible to modify the function in some way to achive this?
  2 Kommentare
Turlough Hughes
Turlough Hughes am 24 Nov. 2019
You would write
function Z = test1(d,b,c)
% operations to get a,l,m.
Z=[a l m];
end
KALYAN ACHARJYA
KALYAN ACHARJYA am 25 Nov. 2019
Bearbeitet: KALYAN ACHARJYA am 25 Nov. 2019
function Z = test1(d,b,c)
a=0;
l=b/sqrt(b^2 + c^2);
m=c/sqrt(d^2 + c^2);
a=a*1;
a=a*-1;
l=l*1;
l=l*-1;
m=m*1;
m=m*-1;
Z=[a l m];
fprintf('Z=[%i %i %i]\n',Z);
end

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Akzeptierte Antwort

Turlough Hughes
Turlough Hughes am 25 Nov. 2019
Bearbeitet: Turlough Hughes am 25 Nov. 2019
Hi Jenny,
You could write your function to have two outputs as follows:
function [Z1,Z2] = test1(d,b,c)
% code to determine a,l,m
Z1=[a,l,m];
Z2=[a,-l,-m];
end
When calling the function you have to specify two outputs if you want them otherwise matlab does not know what to assign the second output to. Basically:
[Z1,Z2]=test1(d,b,c)
Another thing you could do would be to write a single output where you have 6 elements in a single output variable. That would go something like this:
function Z = test1(d,b,c)
% code to get a,l,m
Z=[a,l,m;a,-l,-m];
end
When you call the function now you get a single output with six elements that you are looking for.
I recommend looking at onramp tutorials. Especially part 7 on calling functions as well as vectors and matrices, part 3. Though, if you intend to use matlab much you are as well to go through all of the sections.
  1 Kommentar
Jenny Andersen
Jenny Andersen am 25 Nov. 2019
Thank you alot! It seems to be working very well now. One thing that came to mind is that the value differs a bit from be previous expressions, but I gess that is the way functions work.
I will continue with the Onramp course.

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Weitere Antworten (1)

Jenny Andersen
Jenny Andersen am 25 Nov. 2019
Bearbeitet: Jenny Andersen am 25 Nov. 2019
So I tried Turlough's suggestion again and it seems to be working fine now. But since two vectors will be generated (-d,b,c) and (d,b,-c) I would like to add this information to my code in some way. I have come up with the following, but still I only get one vector.
function [Z] = test1(d,b,c)
a1=0;
l1=b/sqrt(b^2 + c^2);
m1=-c/sqrt(d^2 + c^2);
a=0;
l=-b/sqrt(b^2 + c^2);
m=c/sqrt(d^2 + c^2);
Z=[a1 l1 m1];
Z=[a l m];
end
  1 Kommentar
KALYAN ACHARJYA
KALYAN ACHARJYA am 25 Nov. 2019
Bearbeitet: KALYAN ACHARJYA am 25 Nov. 2019
Why you have deleted your previous comments, its may confuse to the answer providers? This is answer section, please post your comment in comment section only.

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