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Problem using interp1 with a sharp change in the data

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Jaime De La Mota Sanchis
Jaime De La Mota Sanchis on 18 Nov 2019
Hello everyone.
I have a vector of data and I want to interpolate it using interp1. The problem is that there is a sharp increase in the values of the vector and the resulting graph does not reproduce the data propperly.
Is there a way to make the interpolated data reproduce the sharp jump propperly?
I will attach a figure where my issue is displayed.
Any answer is appreciated.
Thank you very much.
Jaime.
  5 Comments
Jaime De La Mota Sanchis
Jaime De La Mota Sanchis on 18 Nov 2019
The code I use is simply
Tinterp=interp1(time,T,t,'spline');
being T a vector which values can be seen in the attached T.txt; the same thing happens with time.
What I do next is plot together T-time and Tinterp and t as
figure
plot(t, Tinterp)
hold on
plot(time, T)
legend('interpolated','original')
title('T Spline')
I hope this clarifies what I am attempting to do.

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Answers (1)

Steven Lord
Steven Lord on 18 Nov 2019
Try using ischange to detect these sharp changes in your data and interpolating using only data in the same "piece" of your curve (where pieces are delimited by the ends of your data sets and the change points) as the points for which you want the interpolated value.

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