Changing composition of Row Matrix (1x9) into a 3x3 Matrix

Im a newbie matlab student who has a project for solving a hydraulic problem with finite element method in Matlab.

So far seems good, but I am having difficult time since I have no background about algorithm and programming.

My problem here is;

1-) Making K{i} into a K1 K2 K3 [ seems not necessary if im not wrong but it would make me feel much safer :) ],

2-) K{1} to K{9} looks like something like this,

[1 2 3 4 5 6 7 8 9]

and I need them to look like

[1 2 3; 4 5 6; 7 8 9]

Yes, I am an idiot.

Sorry for Turkish explanations.

echo off all
clc

nodeX = [0,5,9.17,12,0,5,9.17,12,0,5,8,9.17,12]; % noktalarin x koordinatlari
nodeY = [8,8,8,8,4,4,5.5,5.5,0,0,0,2.83,4]; % noktalarin y koordinatlari
elemX = [5,6,6,7,7,7,5,9,10,11,6,7,7]; % i icin olusan ucgenlerin global nokta karsiliklari
elemY = [1,1,2,2,3,4,6,6,6,6,7,12,8]; % j icin
elemZ = [6,2,7,3,4,8,9,10,11,12,12,13,13]; % k icin

varTable = [];

fprintf("e xi\txj\txk\tyi\tyj\tyk\tck\tci\tcj\tbi\tbj\tbk\tA\n"); % tablo basligini formatla

for i = 1:length(elemX)
    
    % sirasiyla elemanlari okutuyoruz 
    currElemX = elemX(i);
    currElemY = elemY(i);
    currElemZ = elemZ(i);
    
    % i ye karsilik gelen global noktalarin koordinat karsiliklari
    % bulunuyor
    xi = nodeX(elemX(i));
    xj = nodeX(elemY(i));
    xk = nodeX(elemZ(i));
    
    yi = nodeY(elemX(i));
    yj = nodeY(elemY(i));
    yk = nodeY(elemZ(i));
    
    % gerekli hesaplama yapiliyor
    ck = xj - xi;
    ci = xk - xj;
    cj = xi - xk;
    
    bi = yj - yk;
    bj = yk - yi;
    bk = yi - yj;
  
    % alan hesabi
    A = abs(0.5 * (xi * yj + xj * yk + xk * yi - xi * yk - xj * yi - xk * yj));
    
    %dongunun disinda kullanmak icin bulunan degerleri sakla
    varTable = [varTable ; ck,ci,cj,bi,bj,bk,A];
    
    % ekrana uygun formatla yazdiriliyor
    fprintf("%d %.2f\t%.2f\t%.2f\t%.2f\t%.2f\t%.2f\t%.2f\t%.2f\t%.2f\t%.2f\t%.2f\t%.2f\t%.4f\t\n",i,xi,xj,xk,yi,yj,yk,ck,ci,cj,bi,bj,bk,A);
    
end


Kcal= array2table(varTable, 'Variablenames',{'ck','ci','cj','bi','bj','bk','A'}) %K 3x3 matris hesabi icin tablo


%tablodaki degerleri disari cekiyorum sutunlari ayri olarak
%A='Tablename'.'variablename' komutu ile
%n sembolu sondaki sadece karisiklik onlemek amacli

cint=Kcal.ci;
cjnt=Kcal.cj;
cknt=Kcal.ck;

bint=Kcal.bi;
bjnt=Kcal.bj;
bknt=Kcal.bk;
Ant=Kcal.A;

%Transpoze ediyoruz satira cevirmek icin sutun matrisini

bin=bint.';
bjn=bjnt.';
bkn=bknt.';

cin=cint.';
cjn=cjnt.';
ckn=cknt.';

An=Ant.';

%Yazdiracagimiz icin basliklar \t ile tab bosluk biraktirliyor \n ile yeni
%satir yazdiriliyor.

fprintf("e K11\tK12\tK13\tK21\tK22\tK23\tK31\tK32\tK33\n"); % tablo basligini formatla

%Degiskenler icin bos matris

varTable2 = [];

for i=1:height(Kcal) % Kcal sutun olarak dizildigi icin height kullandik.
    
    currcin=cin(i);
    currcjn=cjn(i);
    currckn=ckn(i);
    
    currbin=bin(i);
    currbjn=bjn(i);
    currbkn=bkn(i);
    
    currAn=An(i);
    
    cinn=cin(i);
    cjnn=cjn(i);
    cknn=ckn(i);
    
    binn=bin(i);
    bjnn=bjn(i);
    bknn=bkn(i);
    
    Ann=An(i);
    
    % K Row x Column olarak isimlendirir isek, 3x3 matrisin degerleri
    
    K11=(1/(4 * Ann)) * ( binn^2 + cinn^2);
    K12=(1/(4 * Ann)) * ((binn * bjnn) + (cinn * cjnn));
    K13=(1/(4 * Ann)) * ((binn * bknn) + (cinn * cknn));
    K21=(1/(4 * Ann)) * ((binn * bjnn) + (cinn * cjnn));
    K22=(1/(4 * Ann)) * ((bjnn)^2 + (cjnn)^2);
    K23=(1/(4 * Ann)) * ((bjnn * bknn) + (cjnn * cknn));
    K31=(1/(4 * Ann)) * ((binn * bknn) + (cinn * cknn));
    K32=(1/(4 * Ann)) * ((bjnn * bknn) + (cjnn * cknn));
    K33=(1/(4 * Ann)) * ((bknn)^2 + (cknn)^2);
    
    
   varTable2 = [varTable2 ; K11, K12,K13, K21, K22, K23, K31, K32, K33]; %Degiskenleri tabloya aliyoruz
   
    %%%%%%%%%%%%%%%%% YAZDIRMADA SIKINTI VAR %%%%%%%%%%%%%%%
    
    fprintf("%d %.4f\t%.4f\t%.4f\t%.4f\t%.4f\t%.4f\t%.4f\t%.4f\t%.4f\t%.4f\t\n",i,K11,K12,K13,K21,K22,K23,K31,K32,K33);  
    
    %%%%%%%%%%%%%%%%% YAZDIRMADA SIKINTI VAR %%%%%%%%%%%%%%%
end

Kcal2= array2table(varTable2, 'Variablenames',{'K11','K12','K13','K21','K22','K23','K31', 'K32', 'K33'}) %K 3x3 matris hesabi icin tablo2


%K matrislerini olusturmak icin verilerimiz hazir.
%Siradaki islem bu verileri 3x3 Matrislere yerlestirmek.

% 1.SIRA: K1 K2 K3 VERILERINI AYRI AYRI CEKMEK

%%%%%%%%%%%%%%%%%% BURADA KOPUYORUM %%%%%%%%%%%%%%%%%%%%%%


varTable3 = [];


for i=1:height(Kcal2)
    
    varK = [1:1:i]; %1 den i ye kadar rakamlardan olusan satir matrisi yazdirdik
    
    K{i}=varTable2(i,:); %3x3 matrisleri K{1} K{2} olarak ayirir row matrisi olarak
    
    

end


K1=K{1}

[Daniel M]

help reshape

[Hjodie]

Thanks I will take a look.

Answer 1

[Hjodie]

Problem is solve with the help of reshape function,

However, problem never ends in a newbie world.

with the code of;

K{i}=varTable2(i,:);

I created K1 K2 K3 in cell form but i want them in a double form indeed.

So that's my second question.

[Daniel M]

help cell2mat