How to remove duplicate rows in a matrix by considering the repeated values in a specific column?
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Gayan Lankeshwara
am 23 Okt. 2019
Kommentiert: Zach Williams
am 23 Apr. 2021
%% consider the following example.
A = [1 2 4; 3 5 7;1 5 8; 2 9 4]
In matrix A, column 1 has a duplicate value which is 1. I need to keep the first met value and remove the rest accordingly. At the same time, the indices of non-duplicates should not be changed.
The possible solution should be,
A_without_dup = [1 2 4;3 5 7;2 9 4]
%% only the final row is removed because a duplicate is found in that row based on the value of column 1 in A.
Thanks.
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Mohammad Sami
am 1 Nov. 2019
You can use the unique function to return you the index of the unique values in the first column.
Use the stable keyword so the order is preserved. You can then use the index to keep the unique rows.
[~,uidx] = unique(A(:,1),'stable');
A_without_dup = A(uidx,:);
3 Kommentare
David Linsenbardt
am 12 Jan. 2021
You can also combine rows w/ stable and remove rows where duplicates exist in multiple columns:
[~,uidx] = unique(data(:,[1 2]),'rows','stable');
data = data(uidx,:);
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