How to separate a portion of filename from a file

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S Roy
S Roy am 8 Sep. 2019
Beantwortet: madhan ravi am 8 Sep. 2019
How to separate a portion of filename from a file like I have the file 'scrubbed.MOD_D3_AOD_550.20020112.nc' I just want to extract the '20020112' part

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Adam Danz
Adam Danz am 8 Sep. 2019
Bearbeitet: Adam Danz am 8 Sep. 2019
[~, fname] = fileparts('scrubbed.MOD_D3_AOD_550.20020112.nc');
[~,tok] = regexp(fname,'.(\d+)$','match','tokens');
str = tok{1}{1};
  4 Kommentare
S Roy
S Roy am 8 Sep. 2019
Thanks It really helped.
Adam Danz
Adam Danz am 8 Sep. 2019
Bearbeitet: Adam Danz am 8 Sep. 2019
Glad I could help. The other answers here reminded me to make clear the assumption in my answer that the string of interest is always at the end of the filename (ignoring the final file extension) and is preceeded by a decimal point.

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Weitere Antworten (3)

Stephen23
Stephen23 am 8 Sep. 2019
Simpler:
>> str = 'scrubbed.MOD_D3_AOD_550.20020112.nc';
>> out = regexp(str,'\d{8}','match','once')
out = 20020112
  2 Kommentare
S Roy
S Roy am 8 Sep. 2019
Thanks it works fine
Adam Danz
Adam Danz am 8 Sep. 2019
It is simpler and assumes that the string of interest will always have 8 digits and that will be the only sub-string with 8 digits.

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Image Analyst
Image Analyst am 8 Sep. 2019
Try strsplit():
parts = strsplit('scrubbed.MOD_D3_AOD_550.20020112.nc', '.') % Separate in between dots.
yourNumber = parts{end-1} % Take the next to the last one.
  2 Kommentare
Adam Danz
Adam Danz am 8 Sep. 2019
Bearbeitet: Adam Danz am 8 Sep. 2019
This is also simpler than my answer if the assumptions are true that the string of interest is the 2nd to last segment surrounded by decimal points.
S Roy
S Roy am 8 Sep. 2019
Thanks. Now I know many different ways to do it.

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madhan ravi
madhan ravi am 8 Sep. 2019
regexp('scrubbed.MOD_D3_AOD_550.20020112.nc',...
'\d*(?=\.nc)','match','once')

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