How to separate a portion of filename from a file
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S Roy
am 8 Sep. 2019
Beantwortet: madhan ravi
am 8 Sep. 2019
How to separate a portion of filename from a file like I have the file 'scrubbed.MOD_D3_AOD_550.20020112.nc' I just want to extract the '20020112' part
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Stephen23
am 8 Sep. 2019
Simpler:
>> str = 'scrubbed.MOD_D3_AOD_550.20020112.nc';
>> out = regexp(str,'\d{8}','match','once')
out = 20020112
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Adam Danz
am 8 Sep. 2019
It is simpler and assumes that the string of interest will always have 8 digits and that will be the only sub-string with 8 digits.
Image Analyst
am 8 Sep. 2019
Try strsplit():
parts = strsplit('scrubbed.MOD_D3_AOD_550.20020112.nc', '.') % Separate in between dots.
yourNumber = parts{end-1} % Take the next to the last one.
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madhan ravi
am 8 Sep. 2019
regexp('scrubbed.MOD_D3_AOD_550.20020112.nc',...
'\d*(?=\.nc)','match','once')
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