How select a first value from the binary matrix ?
3 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
vikash kumar
am 19 Aug. 2019
Bearbeitet: Andrei Bobrov
am 22 Aug. 2019
I have below matrix i want to select one value from each column which will be 1 make other 0 at return i will get 10*10 matrix.Selection of 1 such that a11 from 1st column,a22 from 2 column,a13 from the third column,a14 from the 4column and so on and make other value in the column 0.If we go for the indexing is ok for the small matrix but in bigger matrix we don't know the position of the 1 value.So is it possible to changed what i want.I have 1300*500 size matrix this is only for the example.
Thanks in advanced for your help.
matrix = [
0 1 0 0 1 0 0 1 0 1 0 1 1 1 0 1 0 0 1 0
1 1 0 0 1 1 1 0 0 1 0 1 0 1 0 0 1 1 1 1
0 1 1 0 0 1 1 0 1 1 1 0 0 1 1 0 0 0 1 1
0 1 1 1 1 1 1 0 0 0 0 1 0 1 1 0 0 0 1 0
1 1 0 0 0 1 0 0 1 1 1 1 0 0 0 0 0 0 0 1
0 0 0 0 0 1 0 0 1 0 1 1 0 1 1 1 1 1 1 0
1 0 1 0 1 0 0 1 1 0 1 1 0 0 1 0 0 1 0 1
1 1 0 0 1 0 1 0 0 0 0 0 1 1 0 1 1 1 0 1
1 0 1 0 0 1 0 0 1 0 0 0 0 1 1 0 0 0 1 0
0 0 1 0 1 0 1 1 0 0 0 1 1 0 0 0 1 1 0 1
];
1 Kommentar
Akzeptierte Antwort
Andrei Bobrov
am 20 Aug. 2019
Bearbeitet: Andrei Bobrov
am 22 Aug. 2019
out = cumsum(cumsum(matrix)) == 1;
or
out = cumsum(matrix) == 1 & matrix;
Weitere Antworten (1)
Walter Roberson
am 19 Aug. 2019
Bearbeitet: Walter Roberson
am 19 Aug. 2019
[~,idx] = max(matrix);
output = sparse(idx,1:size(matrix,2),1,size(matrix,1),size(matrix,2));
Note: in the case where there are no 1's in a particular column, then this code will pick the first row of that column.
[~,idx] = max(matrix);
output = sparse(idx,1:size(matrix,2),true,size(matrix,1),size(matrix,2));
is potentially more useful for your purposes.
5 Kommentare
Walter Roberson
am 20 Aug. 2019
With your 1300 x 500 array, only 1 in 1300 rows has a non-zero entry for each column, so sparse can be a lot more storage efficient than full(); in my test, the full version takes 41 times more memory.
Siehe auch
Kategorien
Mehr zu Structures finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!