Count the same element in a large rows of one column
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Hello!
I want to count a specific value of matrix in each row of matrix, the size of the matrix is 421 by 1
Thanks
2 Kommentare
Walter Roberson
am 13 Mai 2019
Since you only have one column in each row, then the count for each row will be either 0 (the value is not the target) or 1 (the value is the target), so you can just use
YourMatrix == SpecificValue
Antworten (3)
madhan ravi
am 13 Mai 2019
Bearbeitet: madhan ravi
am 13 Mai 2019
uniquevalue = 9; % for example
nnz(matrix==uniquevalue)
0 Kommentare
KSSV
am 13 Mai 2019
Bearbeitet: KSSV
am 13 Mai 2019
idx = matrix==myvalue ; % this wlill give logical indices
T = nnz(idx) ; % this iwll give you total number of values present
id = find(idx) ; % this will give indices/ positions
If you want to know the repeated values. Use unique
[c,ia,ib] = unique(matrix) ;
If you want along woht count the repeated values:
[a,b]=hist(matrix,unique(matrix))
0 Kommentare
Andrei Bobrov
am 13 Mai 2019
Let A - your vector (421 x 1):
[a,~,c] = unique(A);
out = array2table([a, accumarray(c,1)],'v',{'value','times'});
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