Extract part of a filename from a directory list
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Tom Wright
am 14 Aug. 2012
Kommentiert: Sogand Karbalaieali
am 12 Apr. 2017
Hi, Can anyone please show me a 'nice' way to achieve what I what, preferably without looping.
I have a folder containing multiple files with similar format names 'XXX_YYY_010203.txt'. The numeric part is a timestamp, I would like to extract the timestamps into an array.
Currently my code looks like this:
filelist=dir(folder);
x=regexp({filelist(:).name},'_','split')
x=cellfun(@(x) regexp(x(3),'\.','split'),x)
x=cellfun(@(x) x(1),x)
Which works, but isn't exactly readable.
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Oleg Komarov
am 14 Aug. 2012
I suppose that your filenames always have the date as ddmmyy and it's always at then end:
x = {'XXX_YYY_010203.txt'
'XXX_YYY_020203.txt'};
x = cellfun(@(in) in(end-9:end-4),x,'un',0)
2 Kommentare
Sogand Karbalaieali
am 12 Apr. 2017
Thank you. Also, if all file names do not have the same patterns, those with different name pattern shall be excluded to avoid error in the code.
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