How to make connected circle network in 2D on 144*144 pixel size square plane in matlab ?

Hello Everyone,

I,Shubham saraf want to draw 2D image with (38*38)mm image size black pixel plane and put connected network model of circles on it, with Radius = 0.02 mm, Connected length = 0.24 mm. (1 pixel = 0.2646 mm)

what is the matlab code for it? please response me as soon as possible if any know.

Reference image which type output required, it was attached.

I used this code but get single circle output so now generate network provide loop for it.

Matlab code:

% Create a logical image of a circle with specified
% diameter, center, and image size.
% First create the image.
imageSizeX = 640;
imageSizeY = 480;
[columnsInImage rowsInImage] = meshgrid(1:imageSizeX, 1:imageSizeY);
% Next create the circle in the image.
centerX = 320;
centerY = 240;
radius = 100;
circlePixels = (rowsInImage - centerY).^2 + (columnsInImage - centerX).^2 <= radius.^2;
% circlePixels is a 2D "logical" array.
% Now, display it.
image(circlePixels) ;
colormap([0 0 0; 1 1 1]);
title('Binary image of a circle');

Thank you for your consideration.

Answer 1

[darova]

Use loops

clc , clear

% image size
imageSizeX = 640;
imageSizeY = 480;
[X, Y] = meshgrid(1:imageSizeX, 1:imageSizeY);
I = false(size(X));
% circle centers.
xc = [100 150 200 450 500];
yc = [140 250 350];
% circle radius
radius = 10;
for i = 1:length(xc)
    for j = 1:length(yc)
        circ = (Y - yc(j)).^2 + (X - xc(i)).^2 <= radius^2;
        I = I | circ;
    end
end
% circlePixels is a 2D "logical" array.
% Now, display it.
imshow(I)

title('Binary image of a circle');

[Shubham Saraf]

Thanks Darova,

I used loop code and get solution of circles are arranged in line but I want more improvement to make network of this circles means they all are connected to each other through white pixel line so which length is fixed but width was vary between (5 to 10) then what are the changes doing in this code ? could you please help me more in this matlab code because i am on basic level in matlab.

Running Code :

imageSizeX = 640;
imageSizeY = 480;
[X, Y] = meshgrid(1:imageSizeX, 1:imageSizeY);
I = false(size(X));
% circle centers.
xc = [64 128 192 256 320 384 448 512 576];
yc = [48 96 144 192 240 288 336 384 432];
% circle radius
radius = 10;
for i = 1:length(xc)
    for j = 1:length(yc)
        circ = (Y - yc(j)).^2 + (X - xc(i)).^2 <= radius^2;
        I = I | circ;
    end
end
% circlePixels is a 2D "logical" array.
% Now, display it.
imshow(I)
title('Binary image of a circle');

----------------------------------------------------------------------------------

Output attached image : connected circle.jpg

But want output like this by matlab coding : connected_circle_by_line.jpg

Thank you for consideration and please help me in further step which describe above.

Sincerely,

Shubham Saraf

[darova]

Sure. Think how to loop this example

clc , clear

n = 200;
I = false(n,n);
imshow(I)
r = 30;
[X, Y] = meshgrid(1:n);
c1x = 50; c1y = 50; c2x = 150; c2y = 80;    % circle centers
circ1 = (X - c1x).^2 + (Y - c1y).^2 <= r;   % circle 1
circ2 = (X - c2x).^2 + (Y - c2y).^2 <= r;   % circle 2
I = I | circ1 | circ2;                      % adding to image circles
hLine = imline(gca,[c1x c2x],[c1y c2y]);    % creating line
mask = hLine.createMask();                  % creating pixels of that line
I = I | mask;                               % adding to image line
imshow(I)

[Shubham Saraf]

Hey, Darova

I am applying hLine loop matlab code for generate circle connection by line.

Running Code:

-------------------------------------------------------------------------------------------------------------------------------

n = 320;
m = 240;
I = false(n,m);
imshow(I)
r = 20;
[X, Y] = meshgrid(1:m , 1:n);
c1x = 32; c1y = 24; c2x = 64; c2y = 24; c3x = 96; c3y = 24; c4x = 128; c4y = 24; c5x = 160; c5y = 24;
c6x = 32; c6y = 48; c7x = 64; c7y = 48; c8x = 96; c8y = 48; c9x = 128; c9y = 48; c10x = 160; c10y = 48;
c11x = 32; c11y = 72; c12x = 64; c12y = 72; c13x = 96; c13y = 72; c14x = 128; c14y = 72; c15x = 160; c15y = 72;
c16x = 32; c16y = 96; c17x = 64; c17y = 96; c18x = 96; c18y = 96; c19x = 128; c19y = 96; c20x = 160; c20y = 96;
circ1 = (X - c1x).^2 + (Y - c1y).^2 <= r; circ2 = (X - c2x).^2 + (Y - c2y).^2 <= r; circ3 = (X - c3x).^2 + (Y - c3y).^2 <= r; circ4 = (X - c4x).^2 + (Y - c4y).^2 <= r; 
circ5 = (X - c5x).^2 + (Y - c5y).^2 <= r; circ6 = (X - c6x).^2 + (Y - c6y).^2 <= r; circ7 = (X - c7x).^2 + (Y - c7y).^2 <= r; circ8 = (X - c8x).^2 + (Y - c8y).^2 <= r;
circ9 = (X - c9x).^2 + (Y - c9y).^2 <= r; circ10 = (X - c10x).^2 + (Y - c10y).^2 <= r; circ11 = (X - c11x).^2 + (Y - c11y).^2 <= r; circ12 = (X - c12x).^2 + (Y - c12y).^2 <= r;
circ13 = (X - c13x).^2 + (Y - c13y).^2 <= r; circ14 = (X - c14x).^2 + (Y - c14y).^2 <= r; circ15 = (X - c15x).^2 + (Y - c15y).^2 <= r; circ16 = (X - c16x).^2 + (Y - c16y).^2 <= r;
circ17 = (X - c17x).^2 + (Y - c17y).^2 <= r; circ18 = (X - c18x).^2 + (Y - c18y).^2 <= r; circ19 = (X - c19x).^2 + (Y - c19y).^2 <= r; circ20 = (X - c20x).^2 + (Y - c20y).^2 <= r;
I = I | circ1 | circ2 | circ3 | circ4 | circ5 | circ6 | circ7 | circ8 | circ9 | circ10 | circ11 | circ12 | circ13 | circ14 | circ15 | circ16 | circ17 | circ18 | circ19 | circ20;             
hLine1 = imline(gca,[c1x c5x],[c1y c5y]); hLine2 = imline(gca,[c6x c10x],[c6y c10y]);
hLine3 = imline(gca,[c11x c15x],[c11y c15y]); hLine4 = imline(gca,[c16x c20x],[c16y c20y]);
hLine5 = imline(gca,[c1x c16x],[c1y c16y]); hLine6 = imline(gca,[c2x c17x],[c2y c17y]);
hLine7 = imline(gca,[c3x c18x],[c3y c18y]); hLine8 = imline(gca,[c4x c19x],[c4y c19y]);
hLine9 = imline(gca,[c5x c20x],[c5y c20y]);
mask1 = hLine1.createMask(); mask2 = hLine2.createMask(); mask3 = hLine3.createMask(); mask4 = hLine4.createMask();
mask5 = hLine5.createMask(); mask6 = hLine6.createMask(); mask7 = hLine7.createMask(); mask8 = hLine8.createMask();
mask9 = hLine9.createMask(); 
I = I | mask1 | mask2 | mask3 | mask4 | mask5 | mask6 | mask7 | mask8 | mask9;                             
imshow(I)

----------------------------------------------------------------------------------------------------------------------------

Output : line_connected_circle.jpg which attached.

But I want some improvment in this matlab code to make small and also image size (pixel) : [X*Y] = [640*480] , circle radius (pixel) :10, No. of circle: 81, Connected line width (pixel) : 5,

I want connected_circle_by_line.jpg file type output which i am making in paint but that thing with above dimension size i want to generate in matlab then simulate by flow transport properties.

Please see both attchment and give me suggestion how to improve matlab code for creating same output file result of connected_circle_by_line.jpg

Thanks & Regards,

Shubham Saraf

[darova]

Do you know how "for" loop works?

[Shubham Saraf]

Good Morning, Darova ! sorry for let reply busy in class.

Yes, for loop to repeat specified number of times. its matlab code : for index = values

statements

end

But I was applying this loop there is some error occured which shown below.

-----------------------------------------------------------------------------

Running Code:

imageSizeX = 640;
imageSizeY = 480;
[X, Y] = meshgrid(1:imageSizeX, 1:imageSizeY);
I = false(size(X));
% circle centers.
xc = [64 128 192 256 320 384 448 512 576];
yc = [48 96 144 192 240 288 336 384 432];
% circle radius
radius = 10;
for i = 1:length(xc)
    for j = 1:length(yc)
        circ = (Y - yc(j)).^2 + (X - xc(i)).^2 <= radius^2;
        I = I | circ;
   end
end
% circlePixels is a 2D "logical" array.
% Now, display it.
imshow(I)
title('Binary image of a circle');
hLine = imline(gca,[xc1,xc9],[yc1,yc9]);
mask = hLine.createMask();
I = I | mask;                             
imshow(I)

---------------------------% end of code--------------------------------

It can't run because matrix form written [XC YC] value for creating circle and hLine code syntax required each & every connected point written in separately.

Please help me out to solve this query.

Thank you for your kind of consideration.

Sincerely,

Shubham Saraf

Encl: connected_circle_by_line.jpg (want that type of output with matlab code) <please find the attachment.>

[darova]

Think how to use loops to draw many lines

xc = 64:64:576;        % xc = (first element):(step):(last element)
yc = 48:48:432;
for i = 1:length(xc)
    % imline(gca, [x1 y1], [x2 y2])
    hLine = imline(gca,[xc(1) 1],[xc(1) imageSizeY]);
    mask = hLine.createMask();
    I = I | mask; 
end

Please use special button for code inserting:

[Shubham Saraf]

Thanks Darova to help me for generating network of circle.

I have a desired output but same problem occurred matlab code size was long can't able to apply for loop on

hLine = imline(gca,[x1 x2],[y1 y2]);

My running code was:

imageSizeX = 640;
imageSizeY = 480;
[X, Y] = meshgrid(1:imageSizeX, 1:imageSizeY);
I = false(size(X));

xc = 64:64:576;        
yc = 48:48:432;
r = 10;
for i = 1:length(xc)
    for j = 1:length(yc)
        circ = (Y - yc(j)).^2 + (X - xc(i)).^2 <= r^2;
        I = I | circ;
    end
end
imshow(I)

hLine1 = imline(gca,[1 640],[48 48]);hLine2 = imline(gca,[1 640],[96 96]);hLine3 = imline(gca,[1 640],[144 144]);hLine4 = imline(gca,[1 640],[192 192]);
hLine5 = imline(gca,[1 640],[240 240]);hLine6 = imline(gca,[1 640],[288 288]);hLine7 = imline(gca,[1 640],[336 336]);hLine8 = imline(gca,[1 640],[384 384]);
hLine9 = imline(gca,[1 640],[432 432]);hLine10 = imline(gca,[64 64],[1 480]);hLine11 = imline(gca,[128 128],[1 480]);hLine12 = imline(gca,[192 192],[1 480]);
hLine13 = imline(gca,[256 256],[1 480]);hLine14 = imline(gca,[320 320],[1 480]);hLine15 = imline(gca,[384 384],[1 480]);hLine16 = imline(gca,[448 448],[1 480]);
hLine17 = imline(gca,[512 512],[1 480]);hLine18 = imline(gca,[576 576],[1 480]);

mask1 = hLine1.createMask();mask2 = hLine2.createMask();mask3 = hLine3.createMask();mask4 = hLine4.createMask();
mask5 = hLine5.createMask();mask6 = hLine6.createMask();mask7 = hLine7.createMask();mask8 = hLine8.createMask();
mask9 = hLine9.createMask();mask10 = hLine10.createMask();mask11 = hLine11.createMask();mask12 = hLine12.createMask();
mask13 = hLine13.createMask();mask14 = hLine14.createMask();mask15 = hLine15.createMask();mask16 = hLine16.createMask();
mask17 = hLine17.createMask();mask18 = hLine18.createMask();

I = I | mask1| mask2| mask3| mask4| mask5| mask6| mask7| mask8| mask9| mask10| mask11| mask12| mask13| mask14| mask15| mask16| mask17| mask18;
imshow(I)
title('Binary image of circle connect by line');

My output image:

Now, Help me to solve which I want to compress matlab code by using for loop, how to apply it on above code and also connected line width dimension changes from 1 pixel to 10 pixel.

Thank you for your kind of consideration.

Sincerely,

Shubham Saraf

[darova]

Hi, look attached files. Think how to create origins using loops

Read about imdilate()