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Replace matched values with a cell array keeping unmatched values unchanged

Asked by Shubham Gupta on 15 Apr 2019
Latest activity Commented on by Rik
on 16 Apr 2019
I have a string let's say
A = '[0, 40, 50, 60, 80, 100, 140, 160, 200, 300]';
and another char array, say
B = '48 43 533 6320 840 43 13 13 24 49';
I want to replace numeric values in "A" by numeric values in "B". I tried to match numerical values in B using:
B_num = regexp(A,'\d*','match');
then I tried to replace the numeric values in B without chaging non-numeric values in A using :
A_update = regexprep(A,'\d*',[B_num{:}])
which obivously didn't give the desired results. I know my mistakes but I am unable to really think how I can achieve the desired result.

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1 Answer

Answer by Rik
on 15 Apr 2019
 Accepted Answer

This code should help
A = '[0, 40, 50, 60, 80, 100, 140, 160, 200, 300]';
B = '48 43 533 6320 840 43 13 13 24 49';
B_num = regexp(B,'\d*','match');
A_pad = regexp(A,'\d*','split');
B_num{end+1}=[];%extend to match size of pad
C=[A_pad(:) B_num(:)]';%put the padding and values back together again
C=C(:)';C(end)=[];%make linear and remove empty last element
C=cell2mat(C);%convert back to char array
But please don't use this in a statement with eval...

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