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what's the matter when i run a M.file?

1 Ansicht (letzte 30 Tage)
Huadong Hu
Huadong Hu am 15 Apr. 2019
Geschlossen: MATLAB Answer Bot am 20 Aug. 2021
These below are part of the contents of the M.file i want to run.
clc;
clear all;
clc;
addpath(genpath('Sample_test'));
addpath(genpath('LFToolbox0.4'));
LFMatlabPathSetup;
%% Step1: Decompress data.C.0/1/2/3---> to get white image data
fprintf('===============Step1: Unpack Lytro Files===============\n\n ');
LFUtilUnpackLytroArchive('Sample_test')
These below are the results in the command.
===============Step1: Unpack Lytro Files===============
Searching for files [ data.C.0 ] in Sample_test
??? Error using ==> textscan
First input must be of type double.
Error in ==> LFToolbox0.4\LFFindFilesRecursive.m at 83
FolderList = textscan(FolderList, '%s', 'Delimiter', pathsep);
Error in ==> LFToolbox0.4\LFUtilUnpackLytroArchive.m at 44
[AllVolumes, BasePath] = LFFindFilesRecursive(InputPath, FirstVolumeFname);
Error in ==> Demo at 23
LFUtilUnpackLytroArchive('Sample_test')

Antworten (2)

TADA
TADA am 15 Apr. 2019
textscan accepts a file id not a file path. Use fopen first
  5 Kommentare
TADA
TADA am 15 Apr. 2019
Bearbeitet: TADA am 15 Apr. 2019
Oh.... I can't say much about older versions of Matlab....
@Huadong Hu, you can try using
FileList = regexp(FileList, pathsep, 'split');
Or
FileList = strsplit(FileList, pathsep);
Hopefully that feature did exist back in 2004
Walter Roberson
Walter Roberson am 15 Apr. 2019
strsplit() is r2013a .
regexp() should be there. However after you use regexp with 'split', it is a good idea to use
dirlist = regexp(FolderList, pathsep, 'split');
dirlist(cellfun(@isempty, dirlist)) = [];
FolderList = dirlist;
If Folderlist had happened to begin or end with pathsep or if there had been multiple pathsep in a row, then regexp split would have left an empty cell; the indexing and cellfun is there to delete those empty cells.

Walter Roberson
Walter Roberson am 15 Apr. 2019
You are using MATLAB R14 from 2004 to attempt to run code that was written for R2014a. The code uses features that did not exist in your release.
  1 Kommentar
Huadong Hu
Huadong Hu am 15 Apr. 2019
so install R2014a version?

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