Indice wise reference of indice from another matrix

I search a better writing (without for loop) than the following functionning code.

the code write on the 3rd dimmension of A_delayed wisely to an indice stored in a separate matrice.

For each row,colum of A the 3rd dimmension indice can be different.

        for i10=1:row_A
            for i11=1:colum_A
                A_delayed(i10,i11,matrice_delay(i10,i11))=A(i10,i11);
            end
        end
        

Thank in advance.

[KALYAN ACHARJYA]

Question?

[Valerian Cinçon]

My question is :

how do i write this without for loop ?

or any better way of writing it.

[madhan ravi]

Illustration needed with a simple example.

[Valerian Cinçon]

>> A= [0 1 ; 1 1];
matrice_delay = [1 1 ; 2 3];

A_delayed = zeros (2,2,3);

for i10=1:2
    for i11=1:2
        A_delayed(i10,i11,matrice_delay(i10,i11))=A(i10,i11);
    end
end
>> A_delayed

A_delayed(:,:,1) =

     0     1
     0     0


A_delayed(:,:,2) =

     0     0
     1     0


A_delayed(:,:,3) =

     0     0
     0     1

Answer 1

[Stephen23]

Use ndgrid and sub2ind:

>> A = [0,1;1,1];
>> D = [1,1;2,3];
>> B = zeros(2,2,3);
>> S = size(B);
>> [R,C] = ndgrid(1:S(1),1:S(2));
>> B(sub2ind(S,R,C,D)) = A
B(:,:,1) =
  0  1
  0  0
B(:,:,2) =
  0  0
  1  0
B(:,:,3) =
  0  0
  0  1

[Valerian Cinçon]

Dear Stephen,

Thank you for your wonderful contribution.

Best regards,

Valérian,