Indexing values of an array based on values of one column
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Elina Park
am 3 Okt. 2018
Kommentiert: Elina Park
am 3 Okt. 2018
I'm looking to index a value in a certain row of a matrix, based on the values in one of the columns. For example, if I have an array like this:
[45 1 234 457
58 1 283 384
49 2 384 221
92 2 983 174
97 1 937 123]
How can I index the values in column 3 for values where the value in column 2 of the same row is 1? Without specifying the exact position of the value like column 3, row 1 and such. Is there a way to use logical indexing to do this?
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Image Analyst
am 3 Okt. 2018
Sounds like homework. Is it?
I don't think you can use logical indexing, at least immediately, because they are different lengths -- col 2 has 5 values while row 1 has 4 values. Try using intersect() or ismember() to find the values in common, then use logical indexing. Write back if you need help.
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Image Analyst
am 3 Okt. 2018
OK, here's a further hint to get you started:
m = [45 1 234 457
58 1 283 384
49 2 384 221
92 2 983 174
97 1 937 123]
col2 = m(:, 2)
row1 = m(1, :)
matches = intersect(col2, row1)
[ia, ib] = ismember(col2, row1)
[ia, ib] = ismember(row1, col2)
See if you can take it from there.
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