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How can we get the solution for an 'exact differential equation' dy/dx=(x^2-y^2)/2*x*y in matlab

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abcdr
abcdr on 30 Sep 2018
Commented: madhan ravi on 11 Oct 2018
'exact differential equation'dy/dx=(x^2-y^2)/2*x*y'

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Star Strider
Star Strider on 30 Sep 2018
You seem to have omitted the LHS.
dxdt = (x^2-y^2)/2*x*y
dydt = (x^2-y^2)/2*x*y
dxdy = (x^2-y^2)/2*x*y
dydx = (x^2-y^2)/2*x*y
or something else?
abcdr
abcdr on 30 Sep 2018
My bad. The equation is 2*x*y*(dy/dx)=(x^2)-(y^2). This is an exact equation. How do we find the solution of an exact differential equation in matlab

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Accepted Answer

madhan ravi
madhan ravi on 1 Oct 2018
syms y(x)
ode=2*x*y*(diff(y))==(x^2)-(y^2)
sol=dsolve(ode)

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