# Check if one cell is comprised in other cells of an array?

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Andrew Poissant on 27 Jul 2018
Edited: Andrew Poissant on 27 Jul 2018
I have a variable, var (see attached .mat file), that is a 1x7 cell array. It has the following cells: {766×2 double} {766×2 double} {766×2 double} {766×2 double} {766×2 double} {766×2 double} {766×2 double}.
I want to see if each row of a cell is comprised in another one of the cells in the array. If every single row of a cell is comprised in any of the other cells, then delete that cell. How would I do that? For example, if each row in the first {722x2 double} cell is comprised in any of the other six {766x2}, then delete the first cell.

Jan on 27 Jul 2018
Use ismember('rows') and a loop:
found = true;
for k = 2:7
found = found & ismember(v{1}, v{k}, 'rows');
end
v{1} = v{1}(~found);
Andrew Poissant on 27 Jul 2018
Edited: Andrew Poissant on 27 Jul 2018
how would I generalize this procedure to apply it to the other 6 cells in the array? Also, when I try this with my cell array I uploaded, all it is doing is deleting a row of cell one and some of the columns? What I am looking for is if every row in a cell is shared in any of the other cells in the array, then delete that cell from the array.

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