Im trying to fix a code in my home work, the directions state to Write a *single* statement that shifts row array attendanceValues one position to the left. The rightmost element in shiftedValues also keeps its value. any thoughts

function attendanceValues = ShiftValues(attendanceValues)
% attendanceValues: Array contains 4 elements recording attendence for the last 4 shows

      % Change indexing values
      attendanceValues(1:4) = attendanceValues(2:4);
      attendanceValues = circshift(attendanceValues,-1)
  end

[zachary stallings]

i figured it out all i needed to do was chance the indexing values to: attendanceValues(1:1) = attendanceValues(2:2); attendanceValues(2:2) = attendanceValues(3:3); attendanceValues(3:4) = attendanceValues(4:4);

Answer 1

[Walter Roberson]

      attendanceValues(1:4) = attendanceValues(2:4);

has four output locations, #1, #2, #3, #4, but only 3 input locations, #2, #3, and #4 . That statement cannot succeed.

If you want to copy 3 input values then you need 3 output locations.

[Walter Roberson]

James comments to me:

not helpful

[Walter Roberson]

It is difficult for me to see what more I could have added without giving away the solution to the entire homework problem.

[Eli]

Please give a better hint

Im dying

[DGM]

We assume that the vector always contains exactly 4 elements. The vector is left shifted such that the last element is retained, and the first element is discarded. If the input vector is called A, then the output vector is

A([2:4 4]) % note that there are still 4 elements here, not just 3

[Walter Roberson]

You are copying three input locations. Adjust the assignment so that you have three output locations

attendanceValues(ThreeOutputLocations) = attendanceValues(2:4);

carefully choose ThreeOutputLocations