How to solve an equation with one unknown?

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Ahmad Ghareeb
Ahmad Ghareeb am 28 Feb. 2017
Beantwortet: Walter Roberson am 28 Feb. 2017
For example:
ss = (16*T*do)/pi*(do^4-di^4)
all variables are know except for (di). What is the code to solve it? Thanks in advance!
  3 Kommentare
Roger Stafford
Roger Stafford am 28 Feb. 2017
I like your reply, John. Pencil and paper is certainly the right way to do that problem.
Ahmad Ghareeb
Ahmad Ghareeb am 28 Feb. 2017
This is just an example.

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Walter Roberson
Walter Roberson am 28 Feb. 2017
syms di
syms ss T do %or assign numeric values to the variables
Pi = sym('pi');
eqn = ss == (16*T*do)/Pi*(do^4-di^4);
sol = solve(eqn, di)
The result you get back will be a vector of four elements, reflecting the four roots of the quartic. You can use double(sol) to see the decimal versions of the exact solutions.
Depending on what you are solving, you might encounter cases where you see outputs such as
root(16*2^(1/2)*z^5 - 16*2^(1/2)*di^4*z - 17*pi, z, 1)
root(16*2^(1/2)*z^5 - 16*2^(1/2)*di^4*z - 17*pi, z, 2)
The form root(f(z), z, N) selects from the set of values, z, such that f(z) = 0 -- that is, the roots of the equation. You will sometimes even see this for cubic equations and it is not uncommon for quartic equations; most quintics and above will generate root() forms.

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