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Why bvp4c not works?

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Andriy Kavetsky
Andriy Kavetsky on 29 Oct 2016
Answered: Bill Greene on 30 Oct 2016
I have an error in using bvp4c, my result is wrong
My task is to solve
3*y"+2*y'=x
y(0)=-2
y(1)=6
my matlab code:
dydt=@(x,y)[y(2); y(2)+x];
bc=@(ya,yb)[ya(1)+2; yb(1)-6];
yinit=@(x)[exp(-x); -exp(-x)];
solinit=bvpinit(linspace(0,1,20),yinit);
sol=bvp4c(dydt,bc,solinit);
plot(sol.x,sol.y(1,:))
Could you help me to find what wrong?

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Answers (1)

Bill Greene
Bill Greene on 30 Oct 2016
I think you want: dydt=@(x,y)[y(2); (x-2*y(2))/3];

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