finding roots of the equation
4 Ansichten (letzte 30 Tage)
Ältere Kommentare anzeigen
For several value of n (n=1,2,3,4,...), it was needed to find roots of under equation.
f(n,I)=n*210+(I^2/n)*[(((200-32I)^2)/200)+32]-197
Please help me, how can I find answer by using MATLAB. And please give me answers (value of I) for n=1,2,3,4,5
0 Kommentare
Akzeptierte Antwort
Matt Tearle
am 10 Feb. 2012
You may want to check your function, because it doesn't seem to have any (real) zeros:
f = @(n,I) n*210+(I.^2/n).*((((200-32*I).^2)/200)+32)-197;
figure
I = linspace(-100,100,5001);
y = f(1,I);
plot(I,y)
min(y)
But, the approach would be to define a function handle for f, as above, then set the value of n and apply fzero to the resulting function of one variable ( I ):
f = @(n,I) n*210+(I.^2/n).*((((200-32*I).^2)/200)+32)-197;
I0 = 0; % Make an initial guess
for n = 1:5
g = @(I) f(n,I); % Make a new function from f(n,I) with n fixed
I0 = fzero(g,I0) % Find zero, starting with previous result
end
2 Kommentare
Weitere Antworten (0)
Siehe auch
Kategorien
Mehr zu Subplots finden Sie in Help Center und File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!