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How can I create 2D projections from a 3D object?

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Eric
Eric am 10 Mai 2016
Kommentiert: Seung Jae Lee am 5 Apr. 2023
I know I can use "radon" for creating 1D projections from 2D, but how can I get 2D projections from 3D objects (such as from a 3D file like an STL file).

Antworten (2)

Mike Garrity
Mike Garrity am 10 Mai 2016
One approach is the technique I showed in answers to this question, and this question.
The basic idea is that you take keep the faces of your geometry, but project the vertices onto the plane. That does mean that you've got multiple conincident polys, so it's not good for things like area computation. But if you just want the visual result, it works well and it's simple.
  2 Kommentare
Thomas Cornew
Thomas Cornew am 10 Mai 2018
Hello Mike,
How would I approach this problem if I was trying to solve for the area of the 2d projection?
Naveen Pathak
Naveen Pathak am 7 Jun. 2021
Hi Mike,
I have a simliar problem. Please, could you help me to plot the following:
Thank you.

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Y.S.
Y.S. am 29 Mär. 2023
2 methods I found that I want to place here for future reference:
[1] fast, but only works for convex shapes. Assuming you have a struct (fvIn) with vertices & faces
fvIn.vertices(:,3)=0; % squash all Z coords
verts = fvIn.vertices;
faces = fvIn.faces;
a = verts(faces(:, 2), :) - verts(faces(:, 1), :); % compute area of all triangles
b = verts(faces(:, 3), :) - verts(faces(:, 1), :);
c = cross(a, b, 2);
area2 = 1/2 * sum(sqrt(sum(c.^2, 2))); % Calculate total area, but this gives double the area because the shape is squashed
Ap = area2/2; %
[2] slow, but works for all shapes
Loop over all triangles, project them on the Z=0 plane, create a polyshape and combine(union) it with the other projected triangles
P = fvIn.vertices(fvIn.faces(1,:),1:2);
psSurfTot = polyshape(P);
for N = 2:size(fvIn.faces,1)
P = fvIn.vertices(fvIn.faces(N,:),1:2);
psSurfTMP = polyshape(P);
psSurfTot = union(psSurfTot,psSurfTMP);
end
% calculate projected area
Ap = area(psSurfTot);
I am still looking for a fast method that works for all shapes, but havent found any
  2 Kommentare
Naveen Pathak
Naveen Pathak am 30 Mär. 2023
Thanks "Y.S." at least you showed a kind gesture.
Matlab people are worth-less to help.
However, I have already solved this problem few months ago :)
Seung Jae Lee
Seung Jae Lee am 5 Apr. 2023
Hi, Naveen. How could you solve this problem? Can you please share your findings?

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