Generate a character matrix through indexing and a for loop

1 Ansicht (letzte 30 Tage)
Mae
Mae am 2 Mai 2016
Kommentiert: Mae am 2 Mai 2016
I want to generate a character matrix through indexing and a for loop. This is what I have so far:
top3Table = ones(3,1); %set row dimension
for i = 1:3
Col1= city(top3Pairs(i,1),:);
Col2= city(top3Pairs(i,2),:);
Row = [Col1,Col2];
top3Table(i) = Row
end
city is a character matrix. An example of one of it's entries is 'Manila'.
The following error occurs: In an assignment A(:) = B, the number of elements in A and B must be the same.
I understand why this error is happening but I'm not sure how to fix it. Please advise!

Antworten (1)

Azzi Abdelmalek
Azzi Abdelmalek am 2 Mai 2016
Bearbeitet: Azzi Abdelmalek am 2 Mai 2016
top3Table(i,1:2) = Row
To pre-allocate your matrix:
top3Table = ones(3,2)
  1 Kommentar
Mae
Mae am 2 Mai 2016
A different error pops up: Subscripted assignment dimension mismatch.
Col1 is a character value with 8 characters :/

Melden Sie sich an, um zu kommentieren.

Kategorien

Mehr zu Loops and Conditional Statements finden Sie in Help Center und File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by