I'd like to delete 24th one of "for 1:1:30"

Hi.

I'd like to delete 24th one of "for 1:1:30" Actually, I can run twice to simulate it as below.

for 1:1:23 and for 24:1:30

However, I'd like to do it in one loop.

I have one more question. Can you let me know a function to return number 1( or zero) when an input is negative value like -5.

a= somefuntion (-5)

ANSWER : 1 (or 0)

Thank you.

Best regards,

Jaeyoung Park

[the cyclist]

In the future, I suggest that if you have two questions, split them up into two separate entries.

Answer 1

[Walter Roberson]

There are a number of different ways:

for K = 1 : 30   %#1
  if K == 24; continue; end
  ...
end

for K = setdiff(1:30,24)  %#2
  ...
end

KV = 1:30; KV(24) = [];  %#3
for K = KV
  ...
end

For your second question, again there are multiple ways:

function r = somefunction(v)  %#1
  if v < 0
    r = 1;
  else
    r = 0;
  end
end

function r = somefunction(v)  %#2
  r = 0 + (v < 0);
end

somefunction = @(v) v < 0;    %#3

Answer 2

[the cyclist]

Not sure I understand what you mean by your first question, but for your second one:

function out = isNegative(x)
  out = double(x<0); % Using "double" to convert from logical to numerical value
end

But why not just put "x<0" right in your code, rather than writing a function?

Answer 3

[Jaeyoung]

Thank you guys.

Your comments are very helpful. Thank you.