Three Loops with summation
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Greeting,
I have matrix Z(30,70) and it repeated for 40 times each time there will be new value for each cell. This means for example Z(1,1) will have 40 different values. And the same for all cells in the matrix. My question how I can sum all 40 Z(1,1) for all values. I want to done this for each cell and save the result in matrix K(30,70)
Do I need to do three loops to accomplish that or there is another ways to do it.
Thank you in advance for all ideas.
Regards
1 Kommentar
Walter Roberson
am 24 Okt. 2015
This sounds like the same question as your earlier http://uk.mathworks.com/matlabcentral/answers/250696-summation-of-valuse-in-nested-loops
Antworten (2)
Walter Roberson
am 24 Okt. 2015
If you have a cell array Z and you want sum each of the entries, then
cellfun(@sum, Z)
if you are expecting a 30 x 70 numeric array as output, and otherwise
cellfun(@sum, Z, 'Uniform', 0)
if you are expecting a 30 x 70 cell array as output.
2 Kommentare
Walter Roberson
am 24 Okt. 2015
for L=1:10
for i=1:20
for j=1:100
r=(Xc+Y)^(1/2);
VC=VCo*(1-(exp(-(r))));
Uf(i,j)=(((VC-Yc))/((pi)*(r)));
Vf(i,j)=((VC*r)*(Xc))/((2*pi));
Uft(i,j,L)=Uft(i,j,L)+Uf(i,j);
Vft(i,j,L)=Vft(i,j,L)+Vf(i,j);
Ufz(i,j)=(U-Uft(i,j))/U;
end;
end;
end;
Now afterwards you can use
sum(Utf,3)
sum(Vtf,3)
Matt J
am 24 Okt. 2015
Bearbeitet: Matt J
am 24 Okt. 2015
You should be keeping your Z data as a 3D array of dimension 30x70x40. Then, it's as simple as
K=sum(Z,3);
Example,
>> Z=rand(30,70,40); K=sum(Z,3); whos K Z
Name Size Bytes Class Attributes
K 30x70 16800 double
Z 30x70x40 672000 double
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