amplitude of non-periodic signal

5 Ansichten (letzte 30 Tage)
mustafa alnasser
mustafa alnasser am 2 Okt. 2015
Kommentiert: Star Strider am 3 Okt. 2015
Dear All; if I have a non periodic signal/wave , how can i calculate the amplitude and wavelength ?

Akzeptierte Antwort

Star Strider
Star Strider am 3 Okt. 2015
Another possibility is in the code I used in this Answer. The peak times (the periods are the differences between them) will be in t(zx_idx) and the amplitudes will be in C(zx_idx) in that code.
  2 Kommentare
mustafa alnasser
mustafa alnasser am 3 Okt. 2015
Thank you but where is the code ?
Star Strider
Star Strider am 3 Okt. 2015
It is in my Answer. I am reposting it here:
t = linspace(0, 10, 1000); % Time
C = 2 + sin(2*pi*t + cos(5*pi+t)*pi); % Signal
dC = diff([0, C])/(t(2)-t(1)); % Approximate Derivative
dCzx = dC .* circshift(dC, [0 -1]); % Negative Values => Zero Crossings (Mostly)
zx_idx = find(dCzx <= 0); % Derivative Zeros Are Maxima, Minima Of ‘C’
figure(1)
plot(t, C)
hold on
plot(t(zx_idx), C(zx_idx), 'or')
hold off
grid
axis([xlim 0 5])

Melden Sie sich an, um zu kommentieren.

Weitere Antworten (1)

Image Analyst
Image Analyst am 3 Okt. 2015
As you know, any arbitrary signal can be considered as a weighted sum of a bunch of sine waves - that's the whole concept of Fourier analysis. I suggestion you look at the fft() function or the pwelch() function.
  2 Kommentare
mustafa alnasser
mustafa alnasser am 3 Okt. 2015
Thank you but where is the code ?
mustafa alnasser
mustafa alnasser am 3 Okt. 2015
sorry for the second answer.
For your answer i have already did that but i could not figure out how use FFT to do that

Melden Sie sich an, um zu kommentieren.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by