I have a 3D matrix of size 20*22*815 . What is the way that i can generate 2D matrix of 815 rows and 440(20*22) columns

 Akzeptierte Antwort

Matt J
Matt J am 15 Sep. 2015

1 Stimme

A=permute(yourMatrix,[3,1,2]);
A=A(:,:);

Weitere Antworten (1)

Hamoon
Hamoon am 16 Sep. 2015

0 Stimmen

another possibility:
A = rand(20,22,815); % your matrix
B = reshape(A,440,815)';
The output of this code is equal to Matt's answer.
you can also use B=reshape(A,815,440) without using transpose, then B will be a 815*440 matrix, but the arrangement of data will be different. This is up to you what kind of arrangement you want.

Produkte

Gefragt:

Jab
am 15 Sep. 2015

Kommentiert:

Jab
am 16 Sep. 2015

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by